Wisconsin Public Radio wants to duplicate a survey conducted in 2011 that found that 68% of adults living in Wisconsin felt that the country was going in the wrong direction. How many people would need to be surveyed for a 90% confidence interval to ensure the margin of error would be less than 3%?

Q: In a 2017 survey was conducted on what was the best day of the week.  The result indicated that 90%…

A: Margin of error is given by, And Confidence interval for this study,

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

A:

Q: Suppose you want to produce an estimate on the percent of students who return to college after their…

A:

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: What confidence interval will have the larger margin of error when using the same sample data and…

A: Since we know that, Confidence interval = the estimate ± the margin of error Margin of error is…

Q: Suppose we take a survey of 200 students and ask how much they study per week. The result is an…

A: From the above data  We are given that the  95% confidence interval is (10, 10.5). The population…

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

A:

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: magine that you conduct a study and estimate that the prevalence of hypertension among employees of…

A: It is given that the estimated prevalence is 24%.

Q: sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a 90%…

A: Given that  X=133 , n=624 , p=20%=0.20

Q: A research group asked 4488 Americans how they fall asleep, and 536 of them fall asleep on their…

A: Obtain the 90% confidence interval for the percentage of all Americans who fall asleep on their…

Q: In a random sample of 500 adults, 410 described themselves as vegetarians. Construct a 95%…

A: We have been provided with the following information about the adults who describe themselves as…

Q: According the the U.S. Census bureau, the percentage of Santa Ana residents living in poverty is…

A: Given: p^1=0.177p^2=0.133n1=1200n2=1500

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: The 95​% confidence interval for the proportion that express a great deal of confidence or quite a…

A: A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: A doctor would like to estimate the mean difference in the number of hours of sleep for seniors in…

A: Random sample of 50 high school seniors  Random sample of 50 seniors from the colleges in his county…

Q: A new survey found that out of a random sample of 300 high school students throughout the country…

A: From the provided information, Sample size (n) = 300 83% of them still planned on taking the…

Q: A sample of 1,000 employees in an international company was taken to estimate the average…

A: Confidence interval of mean is given by, (X bar + - Z* sigma/√n) Where X bar is mean and sigma is…

Q: The Gallup Poll interviews 1600 people. Of these, 18% say that they jog regularly. The news report…

A: The formula for the confidence interval of population proportion is (p̂ ± E).

Q: In a survey of 2013 adults in a recent​ year, 731 made a New​ Year's resolution to eat healthier.…

A:

Q: We plan to sample parents in order to construct a 99% confidence interval for the proportion who…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: What is the effect on a confidence interval if one decreases both sample size and the level of…

A:

Q: 3. In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: Given : Sample size of people (n) = 300 Let X : No. of people from sample  who said they watched…

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: A university health services physician is concerned about how much sleep freshman are getting. She…

A: Here we have to find what would happen to the width of the confidence interval if the sample size is…

Q: In a recent survey of 1003 students, 977 of them would like to recommend www.helpyourmath.com to…

A: According to the given information, we have Confidence level = 90% Total number of students = 1003

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.