**Poll Analysis**1. A poll of 2,500 people shows that 50% approve of a smoking ban in bars and restaurants. What is the margin of error, assuming a 95% confidence level? What is the confidence interval?**Explanation:**To calculate the margin of error (MOE) and confidence interval for this poll, use the following steps:1. **Determine the sample proportion (p):** In this case, p = 0.50 (50% approval).2. **Calculate the standard error (SE):** SE = sqrt[(p(1-p))/n] Where n is the sample size (2,500 in this case). SE = sqrt[(0.50 * 0.50) / 2,500] SE = sqrt[0.25 / 2,500] SE = sqrt[0.0001] SE = 0.013. **Find the Z-score for a 95% confidence level:** Typically, the Z-score is 1.96 for a 95% confidence level.4. **Calculate the Margin of Error (MOE):** MOE = Z * SE MOE = 1.96 * 0.01 MOE = 0.0196 or 1.96%5. **Determine the Confidence Interval:** Lower limit = p - MOE = 0.50 - 0.0196 = 0.4804 or 48.04% Upper limit = p + MOE = 0.50 + 0.0196 = 0.5196 or 51.96%Thus, the confidence interval is 48.04% to 51.96%. This means we can be 95% confident that the true proportion of people who approve of the smoking ban is between 48.04% and 51.96%.

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Answered: 1. A poll of 2,500 people shows that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Refer to diagram and apply to multiple choice.
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