In a random sample of 500 children from Illinois, 143 were undernourished. Use these sample data to answer the following questions. p-value 0.000 test statistic is -9.57                                                                                          What sample size would be needed to construct a 95% confidence interval to estimate the proportion of all children in Illinois who are undernourished with a margin of error of ±5%? Use the observed sample proportion from the scenario as an estimate for the population proportion. You will need to do calculations by hand.

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A: The amounts spent on a trip to the mall is 19.36,29.95,7.82,8.36,21.07,14.06,22.22

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A: Given data: Given confidence interval = (19.1 , 48.7 ) Standard deviation  = 42 months Mean = 36.2

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Q: Which of the following is thet-value for a 95% confidence level when the sample size is 20. O a.…

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Q: Construct a confidence interval for the mean of the paired differences for the two populations with…

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Q: What value should be reported as the mean?

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Q: The administration at Pierce College conducted a survey to determine the proportion of students who…

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Q: If n=41n=41, ¯xx¯=36, and s=9s=9, find the margin of error for a 80% confidence level.

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Q: A survey was conducted that asked 1007 people how many books they had read in the past year. Results…

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Q: Estimate 95% confidence interval for the proportion of household experiencing burglary in 2010."

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Q: In a random sample of 144 observations, the sample proportion is 0.90. Construct a 95% confidence…

A: given data sample size (n) = 144P^ = 0.9095% ci p.

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Q: If X=72​, σ=13​, and n=66​, construct a 95​% confidence interval estimate of the population​…

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Q: For a sampling distribution of n = 800 and population proportion of 0.42 of those who prefer cookies…

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Q: If n= 220, p-hat= .4, then what will be the 87.4% confidence interval for the population proportion?

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Q: a. Construct a 99% confidence interval estimate for the population mean number of days between the…

A: Answer:- Given data…

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Q: f. A sample of 60 Grade 10 students' ages was obtained to estimate the mean lot all Grade 9…

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A: Given Information: Under age of 18  n1=480 x1=160 Over age of 18 n2=500 x2=140