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In an experiment with an isolated segment of the ascending loop of Henle, methoxyinulin was added to the perfusate in order to track the volume rate of fluid reabsorbed (R, in nL/min) in the presence or absence of a drug. Based on the following data, what was R? Vin = 2 nL/min Cin = 1000 cpm Cout = 1400 cpm Relevant equations Cin x Vin = Cout x Vout R = Vin - Vout O 1.1 nL/min O 1.0 nL/min O 0.514 nL/min 0.9 nL/min

In an experiment with an isolated segment of the ascending loop of Henle, methoxyinulin was added to the perfusate in order to track the volume rate of fluid reabsorbed (R, in nL/min) in the presence or absence of a drug. Based on the following data, what was R? Vin = 2 nL/min Cin = 1000 cpm Cout = 1400 cpm Relevant equations Cin x Vin = Cout x Vout R = Vin - Vout O 1.1 nL/min O 1.0 nL/min O 0.514 nL/min 0.9 nL/min

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please help me, I have an exam tomorrow, I do not know if my answer is correct, could you please give me the answer to this so I can study with it. 

In an experiment with an isolated segment of the ascending loop of Henle, methoxyinulin was added to the perfusate in order to track the volume rate of fluid reabsorbed (R, in nL/min) in the presence or absence of a drug. Based on the following data, what was R? Vin = 2 nL/min Cin = 1000 cpm Cout = 1400 cpm Relevant equations Cin x Vin = Cout X Vout R = Vin - Vout 1.1 nL/min O 1.0 nL/min O 0.514 nL/min 0.9 nL/min
Transcribed Image Text:In an experiment with an isolated segment of the ascending loop of Henle, methoxyinulin was added to the perfusate in order to track the volume rate of fluid reabsorbed (R, in nL/min) in the presence or absence of a drug. Based on the following data, what was R? Vin = 2 nL/min Cin = 1000 cpm Cout = 1400 cpm Relevant equations Cin x Vin = Cout X Vout R = Vin - Vout 1.1 nL/min O 1.0 nL/min O 0.514 nL/min 0.9 nL/min
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