In an experiment designed to test the output levels of three different treatments, the following results were obtained: SST = 450, SSTR :120, nT19. Set up the ANOVA table and test for anysignificant difference between the mean output levels of the three treatments. Use a = 0.05. Do not round your intermediate calculations.SourceSumDegreesMean SquareFp-value(to 2 decimals)of Variationof Squares of Freedom(to 2 decimals)(to 4 decimals)Treatments120ErrorTotal450The p-value is- Select your answer -What is your conclusion?- Select your answer -

Answered: Image /qna-images/answer/e4dc69b7-6beb-403c-ac75-5c0ab0c61a74.jpg

Answered: In an experiment designed to test the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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One group of accounting students took a distance learning class, while another group took the same course in a traditional classroom. At α = .10, is there a significant difference in the mean scores listed below? Exam Scores for Accounting Students Statistic Distance Classroom Mean scores x¯1x¯1 = 9.7 x¯2x¯2 = 10.0 Sample std. dev. s1 = 2.7 s2 = 2.9 Number of students n1 = 23 n2 = 23 Specify the decision rule. (Round your answers to 3 decimal places. A negative value should be indicated by a minus sign.) Find the test statistic tcalc. (Round your answer to 4 decimal places. A negative value should be indicated by a minus sign.) Use Excel to find the p-value. (Round your answer to 3 decimal places.)
Use the following ANOVA table for regression to answer the questions. Analysis of Variance Source DF SS MS F P Regression 1 291.4 291.4 2.01 0.158 Residual Error 174 25230.0 145.0 Total 175 25521.4 Give the F-statistic and p-value.Enter the exact answers.The F-statistic is =The p-value is =
Á study was conducted that examined the relationship between alcohol consumption and risk of heart attack. In all, 417 men, age 40 or older, were tracked over ten years and the number of that experienced a heart attack was recorded. The participants were grouped by those who totally abstained from alcohol and those that drank moderately. For the results given in the table below, use the chi-squared test to find the p value for NHST at the .05 level. (In SPSS use the Yates continuity correction value.) Heart attack Alcohol Crosstabulation Count Alcohol Abstainer Moderate Total Heart attack No 197 192 389 Yes 9. 19 28 Total 206 211 417 Op= .090 Op= 121 !! Op=.067 Op = .048
The manager of a political party wants to find out the association between the campaign spending (Large, medium and small) and the vote obtained (Majority, Average and minority). Use Chi-squared hypothesis test for association to test that there is an association between the variable in campaign spending and the variable in vote obtained with five percent level of significance. The manager uses MS excel to calculate the Chi-squared stat value and the result is 8.874. Critical value: At 1% = 13.277 :At 5% = 9.488 :At 10% = 7.779 1. State the decision rule 2. Conclusion and decision 3. State the alternative hypothesis and the null hypothesis
An experiment was carried out to compare the sound distortion produced by 4 different types of coating on magnetic tape. The ANOVA table for this data is given below, where X indicates a missing value. Source Degrees of Freedom Sum of Squares Mean Squares IF Treatment X 14.49 X Error X X X Total 49 165.69 Compute the F statistic. Give your answer to 2 decimal places.
A study was conducted to determine if the performance of a certain type of surgery on young horses had any effect on certain kinds of blood cell types in the animal. Fluid samples were taken from each of six foals an hour after the operation. Suppose that the data on WBC leukocytes follow the normal distribution. One sample Chi-squared test for variancedata: wbcX-squared = 3.5321, df = 5, p-value = 0.3815alternaative hypothesis: true variance is less than 4 Question: Is there evidence to say that the variance of WBC leukocytes is less than 4? State the conclusion based from the results of the test. Choices:- There is no sufficient evidence that the variance of WBC leukocytes is less than 4.- There is a sufficient evidence that the variance of WBC leukocytes is less than 4.
A sample of 33 lights in Austin gives an average of 46 cars/min while the city SD=3.4 A sample of 34 Dallas lights give a mean of 44 cars/mim with the city SD=1.4 At the 91% level, do the towns differ? 1. Is the test (A-Left Tailed, B-Right Tailed, C-2-Tailed) (separate with comma if there are 2) 2. Critical Value 3. Test statistic 4. 3-decimal p-Value
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A test was conducted on the differences in academic performance of three groups of students subjected to different teaching strategies. Below is the ANOVA table of the results of data analysis. Source F- MS Ratio critical value F- P- of df SS variation Among 3 2100 MST groups ??? 3.18 0.036 Within 45 10000 MSE group
An analysis is conducted to compare mean time to pain relief (measured in minutes) under four competing treatment regimens. Summary statistics on the four treatments are shown below. Complete the following ANOVA Table. Source of Variation SS df MS F Between Groups Within Groups 3719.48 Total
A quality control expert at a local dairy claims that its cartoons contain more than 64oz of milk a sample of 15 cartoons reveals a mean of 65 and 1.1 oxs respectively. At the 1% level, does the appropriate hypothesis support his claim? find and interpret the p value
The valve pressure was tested on 250 engines and the mean pressure was 5.9 lbs/square inch. Assume the variance is known to be 0.36. If the valve was designed to produce a mean pressure of 5.8 lbs/square inch, is there sufficient evidence at the 0.02 level that the valve performs about the specifications?

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