In an experiment, 10.0 g of NajPO4 is mixed with 20.0 g of Pb(NO3)2 and the two react are allowed to react according to the reaction: Na:PO4 (aq) + Pb(N0:)2 (aq) → NaNO: (aq) + Pb:(PO4)2 (s) The following molar masses have been calculated to assist you: M„(Na PO,) = 163.9 g/mol Ma(Pb(NO):) = 331.2 g/mol Ma(NANO)) = 85.0 g/mol M(Pb,(PO,);) = 811.5 g/mol a) Write the balanced chemical reaction. b) Which is the limiting reactant?

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6. In an experiment, 10.0 g of Na3PO4 is mixed with 20.0 g of Pb(NO3)2 and the two reacta
are allowed to react according to the reaction:
NasPO4 (aq) + Pb(NO:)2 (aq) → NaNO3 (aq) + Pb3(PO4): (s)
The following molar masses have been calculated to assist you:
M(Na PO4) = 163.9 g/mol
Ma(Pb(NO3)2) = 331.2 g/mol
Ma(NANO3) = 85.0 g/mol
M(Pb3(PO4)2) = 811.5 g/mol
a) Write the balanced chemical reaction.
b) Which is the limiting reactant?
Transcribed Image Text:6. In an experiment, 10.0 g of Na3PO4 is mixed with 20.0 g of Pb(NO3)2 and the two reacta are allowed to react according to the reaction: NasPO4 (aq) + Pb(NO:)2 (aq) → NaNO3 (aq) + Pb3(PO4): (s) The following molar masses have been calculated to assist you: M(Na PO4) = 163.9 g/mol Ma(Pb(NO3)2) = 331.2 g/mol Ma(NANO3) = 85.0 g/mol M(Pb3(PO4)2) = 811.5 g/mol a) Write the balanced chemical reaction. b) Which is the limiting reactant?
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