A precipitation reaction occurs when 655 mL of 0.639 M Pb(NO2), reacts with 313 mL of 0.855 M KI, as shown by the following equation. Pb(NO3)2(aq) 2 KI(aq)Pbl, (s) + 2 KNO3 (aq) Identify the limiting reactant. O Pb(NO3)2 O KI O Pbl2 Ο ΚNO, KNO3 Calculate the theoretical yield of PbI, from the reaction. mass of Pbl,: Calculate the percent yield of PbI, if 48.0 g of Pbl, are formed experimentally. percent yield of PbI,:

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A precipitation reaction occurs when 655 mL of 0.639 M Pb(NO2), reacts with 313 mL of 0.855 M KI, as shown by the
following equation.
Pb(NO3)2(aq) 2 KI(aq)Pbl, (s) + 2 KNO3 (aq)
Identify the limiting reactant.
O Pb(NO3)2
O KI
O Pbl2
Ο ΚNO,
KNO3
Calculate the theoretical yield of PbI, from the reaction.
mass of Pbl,:
Calculate the percent yield of PbI, if 48.0 g of Pbl, are formed experimentally.
percent yield of PbI,:
Transcribed Image Text:A precipitation reaction occurs when 655 mL of 0.639 M Pb(NO2), reacts with 313 mL of 0.855 M KI, as shown by the following equation. Pb(NO3)2(aq) 2 KI(aq)Pbl, (s) + 2 KNO3 (aq) Identify the limiting reactant. O Pb(NO3)2 O KI O Pbl2 Ο ΚNO, KNO3 Calculate the theoretical yield of PbI, from the reaction. mass of Pbl,: Calculate the percent yield of PbI, if 48.0 g of Pbl, are formed experimentally. percent yield of PbI,:
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