In a t-test which tests the difference between two sample means, if the t-statistic (t) is 0, this implies: μ1 μ2 Ybar₁ - Ybar2 = 0 μ₁ −μ₂0 Ybar₁-Ybar2# 0
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- A random sample of size 24 and mean 2.547 was selected from normal distribution if we want to test that the population mean is less than 5.547, knowing that the sample variance 25, the critical value for alpha =0.01 is? a. 2.807 b. 2.500 c. 2.547 d. 2.33A sample of n=4 scores has ΣX=8 and ΣX2=40. What is the value of the sample variance, s2?14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…
- A newly installed automatic gate system was being tested to see if the number of failures in 1,000 entry attempts was the same as the number of failures in 1,000 exit attempts. A random sample of eight delivery trucks was selected for data collection. Do these sample results show that there is a significant difference between entry and exit gate failures? Use α = 0.05. Truck 1 Truck 2 Truck 3 Truck 4 Truck 5 Truck 6 Truck 7 Truck 8 Entry failures 40 42 53 55 62 54 50 42 Exit failures 47 52 56 56 60 46 52 45 (b) Find the test statistic tcalc. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) tcalc (c) Find the critical value tcrit for α = 0.05. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) tcrit (d) Find the p-value. (Round your answer to 4 decimal places.) p-valueFor a repeated-measures study comparing two treatment conditions, a researcher obtains a sample of n = 10 difference scores with a mean of MD = 6 and a variance of s2 = 90. What is the value for the repeated-measures t statistic for these data? Select one: a. 7 b. 6 c. 2 d. 15The effectiveness of surgery for weight loss reported here found that "The surgery was associated with significantly greater weight loss [than the control group who dieted] through 2 years (61.3 versus 11.2 pounds, P<0.001)." What test could have been used and how would it have been computed?
- A repeated-measures ANOVA was calculated with df = 1, 14. If the same data were analyzed with a repeated-measures t test, how many degrees of freedom would be used with the t statistic?Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…One study compared the differences between the expected values of two groups, i.e. tested the null hypothesis that the expected values are equal. The sample size of the first group (x-observations) was 55 and the sample size of the second group (y-observations) was 60. The following data was obtained.X=113.6, Y= 111.7S2x=32.4S2y=30.1Assume large sample sizes and use a test size and two-tailed test appropriate for this setting. Calculate the p-value of the test. Give the answer to two decimal places. Remember the correct decimal separator.