In a study of the decomposition of nitrous oxide at 565 °C N20(g)N2(g) + ½ 02(g) the concentration of N20 was followed as a function of time. It was found that a graph of 1/[N20] versus time in seconds gave a straight line with a slope of 1.60x10-3 M-1 s1 and a y-intercept of 0.775 M1. Based on this plot, the reaction is order in N20 and the rate constant for the reaction is zero M-1 s1, first second

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section11.1: Reaction Rate
Problem 11.3CE
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In a study of the decomposition of nitrous oxide at 565 °C
N20(g)N2(g) + ½ 02(g)
the concentration of N20 was followed as a function of time.
It was found that a graph of 1/[N20] versus time in seconds gave a straight line with a slope of
1.60x10-3 M-1 s1 and a y-intercept of 0.775 M1.
Based on this plot, the reaction is
order in N20 and the rate constant for the reaction is
zero
M-1s-1,
first
second
Transcribed Image Text:In a study of the decomposition of nitrous oxide at 565 °C N20(g)N2(g) + ½ 02(g) the concentration of N20 was followed as a function of time. It was found that a graph of 1/[N20] versus time in seconds gave a straight line with a slope of 1.60x10-3 M-1 s1 and a y-intercept of 0.775 M1. Based on this plot, the reaction is order in N20 and the rate constant for the reaction is zero M-1s-1, first second
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