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Chorine monoxide accumulates in the stratosphere above Antarctica each winter and plays a key role in the formation of the ozone hole above the South Pole each spring. Eventually, CIO decompses according to the equation: CIO(g) ---> Cl2(g) + O2(g). When 1/[CIO] is plotted vs. time(s), a straight line with slope of 7.22x10° results. What is the rate law for the reaction? O Rate = 7.22x10° M-1 s-1[Cioj? O Rate = 7.22x10º s-1[cio]1 O Rate = 7.22x10° m1 s-1 [CIO] O Rate = 7.22x10º m²² s-1 [Cioj?

Chorine monoxide accumulates in the stratosphere above Antarctica each winter and plays a key role in the formation of the ozone hole above the South Pole each spring. Eventually, CIO decompses according to the equation: CIO(g) ---> Cl2(g) + O2(g). When 1/[CIO] is plotted vs. time(s), a straight line with slope of 7.22x10° results. What is the rate law for the reaction? O Rate = 7.22x10° M-1 s-1[Cioj? O Rate = 7.22x10º s-1[cio]1 O Rate = 7.22x10° m1 s-1 [CIO] O Rate = 7.22x10º m²² s-1 [Cioj?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Chorine monoxide accumulates in the stratosphere above Antarctica each winter and plays a key role in the formation of the ozone hole above the South Pole each spring. Eventually, CIO decompses according to the equation: CIO(g) ---> Cl2(g) + O2(g). When 1/[CIO] is plotted vs. time(s), a straight line with slope of 7.22x10° results. What is the rate law for the reaction? O Rate = 7.22x10º m-1 s-1[Cio? Rate = 7.22x10° sCioj1 Rate = 7.22x10° M1s1 [CIO] O Rate = 7.22x10º M² s1 [Cio]?
Transcribed Image Text:Chorine monoxide accumulates in the stratosphere above Antarctica each winter and plays a key role in the formation of the ozone hole above the South Pole each spring. Eventually, CIO decompses according to the equation: CIO(g) ---> Cl2(g) + O2(g). When 1/[CIO] is plotted vs. time(s), a straight line with slope of 7.22x10° results. What is the rate law for the reaction? O Rate = 7.22x10º m-1 s-1[Cio? Rate = 7.22x10° sCioj1 Rate = 7.22x10° M1s1 [CIO] O Rate = 7.22x10º M² s1 [Cio]?
Expert Solution
Step 1

The reaction given is,

=> 2 ClO (g) → Cl2 (g) + O2 (g)

Given: Plot of 1/[ClO] v/s time is a straight line with slope = 7.22 × 109 

 

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