In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. Foreach shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose thefollowing data were collected.LightHeavyNonbrowserBrowserBrowser410126.10341279.44111045125. a. Use a = .05 to test for a difference among mean comfort scores for the three types of browsers.Compute the values identified below (to 2 decimals, if necessary).Sum of Squares, Treatment89.33Sum of Squares, Error24.5Mean Squares, Treatment44.67Mean Squares, Error1.16Calculate the value of the test statistic (to 2 decimals, if necessary).21The p-value isless than .01What is your conclusion?Conclude that the mean comfort scores are not all the same for the browser groupsb. Use Fisher's LSD procedure to compare the comfort levels of nonbrowsers and light browsers. Use a = .05.Compute the LSD critical value (to 2 decimals).38.28What is your conclusion?Cannot conclude that nonbrowsers and light browsers have different mean comfort scores

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Description: In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. Foreach shopper, the study obtained a measure to determine how comfortable the shopper was in

Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case you require the unanswered parts also, kindly re-post that parts separately. a) Excel Procedure: Enter the data for Non-browser, Light Browser and Heavy Browser in Excel sheet. Go to Data Click on Data Analysis. Select ‘Anova: single factor’ and click on ‘OK’ Select A1:C9 (A: Non-browser, B: Light Browser, C: Heavy Browser) under ‘input range’. Click on ‘OK’. Excel Output: From the output, Sum of squares, Treatments is 196 Sum of squares, Error is 24.5 Mean squares, Treatment is 98 Mean squares, Error is 1.16 From the output, the value of the test statistic is F=84. P value is 0.0000, which is less than 0.01. Conclusion: The mean comfort scores are not all the same for the browser groups.

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In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the Following data were collected. Light Heavy Nonbrowser Browser Browser 4 5 10 5 12 6 5 10 4 12 7

In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the Following data were collected. Light Heavy Nonbrowser Browser Browser 4 5 10 5 12 6 5 10 4 12 7

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the following data were collected. Light Нeavy Nonbrowser Browser Browser 10 4 10 6. 11 12 4 11 10 10 4 11 10 a. Use a = .05 to test for a difference among mean comfort scores for the three types of browsers.