A scientific study was conducted to determine the hours of sleep that college students get per night. Thestudy surveyed 24 college students and obtained the following data:8.2, 7.9, 9, 8, 9.1, 7.8, 8.4, 8.4, 7.3, 7.4, 8.5, 7.4, 7.9, 7.7, 9.7, 9.1, 7.1, 7.9, 7.8, 8.1, 8.3, 8.2, 6.5, 10.3Assuming the population standard deviation is o =average hours of sleep per night that college students get.1.01, construct a 97% confidence interval for theΖαMargin of Error: EWe are 97% confident that college students get an average of betweenhours andhours of sleep per night.

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Answered: A scientific study was conducted to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 57 people she sampled who work out in the morning have a mean of 4.8 hours of exercise each week. The 56 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.3 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2 : Construct a 95% confidence interval for the true difference between the mean amounts…
The following data set lists the mid-term scores received by 50 students in a QuantitativeMethods’ class:45, 85, 92, 99, 37, 68, 67, 78, 81, 25,97, 100, 82, 49, 54, 78, 89, 71, 94, 87,21, 77, 81, 83, 98, 97, 74, 81, 39, 77,99, 85, 85, 64, 92, 83, 100, 74, 68, 72, 65, 84, 89, 72, 61, 49, 56, 97, 92, 82 i. Calculate the first, second, and third quartiles of the mid-terms scoresii. Calculate the interquartile range. What can you conclude from this?
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
A researcher would like to know which factors are most important to people who are buying a new car. A sample of n=200 customers between the ages of 20 and 29 are asked to identify the most important factor in the decision process: Performance, Reliability, or Style. The researcher would like to know whether there is a difference between the factors identified by women compared to those identified by men. The data are as follows: Observed Frequencies of Most Important Factors According to Gender: Performance Reliability Style Total Male 21 33 26 80 Female 19 67 34 120 Total 40 100 60 Compute the expected frequencies (fill in chart). Expected Frequencies: Performance Reliability Style Male Female
Does the type of instruction in a college statistics class (either lecture or self-paced) influence students’ performance, as measured by the number of quizzes successfully completed during the semester? Twelve students were recruited for the study. Students received the lecture instruction or a self-paced instruction. The total number of quizzes completed during teach type of instruction appear below.
An educational psychologist is interested in whether using a child’s own name in a story affected attention span while reading. Six children were randomly assigned to read a story under ordinary conditions (using common and generic names). Five other children read versions of the same story, but with each child’s ownname substituted for one of the children in the story. The researcher measured the amount of time (in minutes) each child spent reading the story. The results are shown in the following table. Does including the child’s namemake any difference in attention span? Test the hypothesis at an alpha set to .05, following these steps: a) write the null and alternative hypotheses; b) determine the critical value(s); c) draw the comparison distribution with rejection region(s) shaded; d)use the correct formula to compute the test statistic; e) state the statistical decision; f) state a brief conclusion.
Bank of America’s Consumer Spending Survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries, dining out, household expenses, home furnishings, apparel, and entertainment. Using data from a sample of 42 credit card accounts, assume that each account was used to identify the annual credit card charges for groceries (population 1) and the annual credit card charges for dining out (population 2). Using the difference data, the sample mean difference was d= $850, and the sample standard deviation was sd= $1123.a. Formulate the null and alternative hypotheses to test for no difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.b. Use a .05 level of significance. Can you conclude that the population means dif-fer? What is the p-value?c. Which category, groceries or dining out, has a higher population mean annual credit card charge? What is the…
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