In a recent survey of 850 homeowners, 3 in 10 homeowners report having a home equity loan that he or she is currently paying off. Construct the 90% confidence interval for the proportion of all homeowners that hold a home equity loan. 0.2610, 0.3259 0.2610, 0.3120 0.2641, 0.3359 0.2741, 0.3259

Q: 800 people took part in market research. 40.8% of those people said that they accept that a new…

A: We have given that  Sample size =800 ,  Sample proportion p^=40.8%=0.408 95% confidence interval…

Q: A poll showed that 48 out of 120 randomly chosen graduates of AUAF work in the government. What is…

A: The confidence interval is calculated using the sample statistic, critical value and the standard…

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage.  Find the 99%…

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Q: In the 2021-22 season, Klay Thompson made 114 out of 296 three point shots. Create a 95% confidence…

A: Solution: Given information: n= 296 Sample size  x= 114 successes p^=xn=114296=0.3851 Sample…

Q: confidence interval for the proportion of unemployed adults who have been unemployed for more than…

A: Here given  In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

Q: A bank randomly selected 253 checking account customers and found that 115 of them also had savings…

A: Given information: It is given that a bank randomly selected 253 checking account customers and…

Q: Out of 180 randomly selected adults in the United States who were surveyed, 81 exercise on a regular…

A:

Q: In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada. Calculate…

A:

Q: 2. n(1-P)= 3. N= If no N is given in the problem, use 1000000 N: Name the procedure The conditions…

A: Point and Interval estimate

Q: Consultant for an association of personal directors wants to find out what proportion of clerical…

A: Given, Sample size, n= 400 And X= 200 Proportion, p= X/n p= 200/400 = 0.5 q= 1-p = 1-0.5 = 0.5 Mean=…

Q: A recent study showed that among 725 randomly selected subjects who completed 4 years of college,…

A: We have given that,  Favorable cases (X) = 139 and Sample size    (n) = 725 Then,  We will find 95%…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: A random sample of 150 mortgages was selected. From this sample, 17 were found to be delinquent on…

A: A confidence interval is a statistical concept that has to do with an interval that is used for…

Q: An internet service provider sampled 1000 of its customers, 189 of them experienced an interruption…

A: It is given that sample size (n) is 1000 and x is 189.

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: In a survey conducted by a reputable marketing agency, 231 of 1000 adults 19 years of age or older…

A: Given Data Sample Size, n = 1000 Number of successes, x = 231.0 Significance…

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

A:

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…

Q: Out of 157 randomly selected adults in the United States who were surveyed, 77 exercise on a regular…

A:

Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…

A: The objective of the question is to understand the meaning of the given 96% confidence interval for…

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made…

A:

Q: In a random sample of 100 drivers, 80 were using seat belts while driving. Construct a 95%…

A:

Q: In a survey of 1118 U.S. adults conducted in 2012 by the Financial Industry Regulatory Authority,…

A: Number of adults in the survey is n=1118 . Number of adults who said that they always pay their…

Q: A magazine publisher wishes to determine what proportion of current subscribes will renew. The…

A: we have given that  sample size n=200 and favorable cases x=108  sample proportion p^= x/n =108/200…

Q: According to a recent Government survey, 6% of all merchandise sold in the U.S. gets returned.  A…

A: It is given that sample size (n) is 80 and x is 12.

Q: Construct a 95% confidence interval for the true proportion of checking account customers who also…

A:

Q: Of 848 children surveyed, 144 plan to join a volunteer group in the future. Construct a 90%…

A: We have given that n=848, X=144, C.I=90%=0.90

Q: A survey of 80 recent arcanum students showed that 46 were ready for summer break. Find the 95%…

A: Obtain the 95% confidence interval for the true proportion of students ready for summer break. The…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…