Of 848 children surveyed, 144 plan to join a volunteer group in the future. Construct a 90% confidence interval for p.

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: Of 260 employees selected randomly from one company, 18.46 % of them commute by carpooling.…

A: Given data, n=260 p= 18.46% = 0.1846   The z value at 90% confidence is 1.64

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Of 41 bank customers depositing a check, 22 received some cash back. Construct a 90% confidence…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Solution

Q: A survey of 400 students at Red Rock College found that 180 planned to take summer classes. Find a…

A:

Q: In a survey of 1005 adults 526 stated construct a 95% confidence interval

A:

Q: A random sample of 320 medical doctors showed that 162 had a solo practice. Let p represent the…

A: Given,

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: Out of a random sample of 60 freshman at State University, 25 students have declared a major. Find a…

A: Given, Out of a random sample of 60 freshman at State University, 25 students have declared a major.…

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: a survey of 1083 people, 585 answered "yes" to a particular question. Construct a 90% confidence…

A:

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: In a survey of 2480 golfers, 15% said they were left-handed. The survey's margin of error was 3%.…

A: It is given that, p^=15%=0.15 Margin of error, E =3%=0.03

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: n a randomly selected group of 750 automobile deaths, 240 were alcohol related. Construct a 95%…

A: Given that,  x = 240, n = 750 The value of sample proportion is,

Q: 2. Construct a 95% confidence interval to estimate the proportion of Wingate female students that…

A: total number of female students =181 number of students who are left handed=15

Q: A survey of 800 women shoppers found that 15% of them shop on impulse.  What is the 95% confidence…

A: n = 800p^ = 0.1595% CI for p = ?

Q: An interactive poll found that 397 of 2,391 adults aged 18 or older have at least one tattoo. A.…

A: Given data: Sample size (n) = 2391 x = 397 adults To construct: 1.95 % confidence interval 2.98%…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: Of 2019 employees selected randomly at a company, 10% of them commute by carpooling. Construct a 90%…

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Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

A:

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: In a survey of 3102 adults,1401 say they have started paying bills online in the last year.…

A: Obtain the 99% confidence interval for the true population proportion. The 99% confidence interval…

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given that, X = 118 N = 200 99% confidence level

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Givenx=316sample size(n)=391Confidence level=95%p^=xn=316391≅0.8082

Q: Out of 100 people sampled 48 had kids. Based on this construct a 90% confidence interval for the…

A:

Q: Of 346 items tested, 22 are found to be defective. Construct the 98% confidence interval for the…

A: Solution: Let X be the number of items found to be defective and n be the sample number of items…

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: Insurance companies are interested in knowing the popul drivers who always buckle up before riding…

A: Given data,No of people surveyed n=387who claims to buckle up is x=311Construct a 93 % CI?

Q: A sanatorium conducted a study on 3,500 women over 35 years of age, of whom 220 reported having…

A: Step 1: State the given data: number of favorable cases, x = 220sample size, n = 3500confidence…

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: Find a 95% confidence interval for the true population proportion.   In a poll of 1079 college…

A: The value of z at 95% confidence level is 1.96, which can be obtained by using the standard normal…

Q: Out of 54 randomly selected patients of a local hospital who were surveyed, 49 reported that they…

A: Giventotal patients randomly selected =n = 54total patients who were satisfied = 49proportion of…

Q: Out of a survey of 900 adults, 567 said that teenagers were more dangerous drivers than senior…

A: Givensample size(n)=900No.of adults said that teenagers were more dangerous divers(x)=567sample…

Q: A magazine publisher wishes to determine what proportion of current subscribes will renew. The…

A:

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…