- In a project, Tow asphalt base course samples was token after paver that have been designed by Marshall method Sample One made form of 51 % of Dolomite and the rest form limestone with binder content 4.3% in sample Two, Limestone was used only with binder content 5 % as showed in the table below. Sample One Sample Two Location G(g/cm Gb (g/cm³) If you know that G-1.03 g/cm³ and Ga Dolomite-2.72 g/cm³. G limestone-2.51 g/cm³ find Which one will meet the specifications? 0+000 to 0+750 2.5 2.4 0+750 to 1+450 2.444 2.35
- In a project, Tow asphalt base course samples was token after paver that have been designed by Marshall method Sample One made form of 51 % of Dolomite and the rest form limestone with binder content 4.3% in sample Two, Limestone was used only with binder content 5 % as showed in the table below. Sample One Sample Two Location G(g/cm Gb (g/cm³) If you know that G-1.03 g/cm³ and Ga Dolomite-2.72 g/cm³. G limestone-2.51 g/cm³ find Which one will meet the specifications? 0+000 to 0+750 2.5 2.4 0+750 to 1+450 2.444 2.35
Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter18: Bituminous Materials
Section: Chapter Questions
Problem 5P: Given the specifications for an asphaltic concrete mixture and the results of a sieve analysis,...
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Question
![Q2)
A- In a project, Tow asphalt base course samples was token after paver that have been designed by
Marshall method Sample One made form of 51 % of Dolomite and the rest form limestone with
binder content 4.3% in sample Two, Limestone was used only with binder content 5 % as showed
in the table below.
Gab =
Location
G(g/cm
Gb (g/cm³)
If you know that G-1.03 g/cm³ and G Dolomite-2.72 g/cm³. G limestone-2.51 g/cm³ find
Which one will meet the specifications?
Gre=
.
P₁+ P₂ +P
P1+
G₁
P2.
G₂
Un
Gmm =
FL
Five Fo
VMA 100-
Sample One
.
0+000 to 0+750
2.5
2.4
P1002
Gmb P
Gab
Sample Two
G-G
Gre Gab
0-750 to 1+450
2.444
2.35
V₁=100-
Gb
.
Gom Gmb
Gmm
Pbe= Pb-P₁
100
.VFA==
100 (VMA-V)
VMA](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c284626-56a4-459b-b8d4-75b2a65a71c3%2F55aaec21-042e-46bf-8fe4-23264cd7a69e%2Fekhqpvd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2)
A- In a project, Tow asphalt base course samples was token after paver that have been designed by
Marshall method Sample One made form of 51 % of Dolomite and the rest form limestone with
binder content 4.3% in sample Two, Limestone was used only with binder content 5 % as showed
in the table below.
Gab =
Location
G(g/cm
Gb (g/cm³)
If you know that G-1.03 g/cm³ and G Dolomite-2.72 g/cm³. G limestone-2.51 g/cm³ find
Which one will meet the specifications?
Gre=
.
P₁+ P₂ +P
P1+
G₁
P2.
G₂
Un
Gmm =
FL
Five Fo
VMA 100-
Sample One
.
0+000 to 0+750
2.5
2.4
P1002
Gmb P
Gab
Sample Two
G-G
Gre Gab
0-750 to 1+450
2.444
2.35
V₁=100-
Gb
.
Gom Gmb
Gmm
Pbe= Pb-P₁
100
.VFA==
100 (VMA-V)
VMA
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