In a certain year, there were 80 days with measurable snowfall in Denver, and 63 days withmeasurable snowfall in Chicago. A meteorologist computes (80 + 1)/(365 + 2) = 0.22, (63 +1)/(365 + 2) = 0.17, and proposes to compute a 95% confidence interval for the differencebetween the proportions of snowy days in the two cities as follows:0.22 – 0.17 + 1.961(0.22)(0.78), (0.17)(0.83)367367Is this a valid confidence interval? Explain.

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Answered: In a certain year, there were 80 days…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A psychologist is interested in whether hypnosis affects brain dominance. Twelve college students from the freshmen class are randomly sampled for an experiment. The experiment has two conditions which are given on different days. In condition 1, the students are hypnotized and then given a test which measures the relative dominance of the right and left hemispheres. The higher the score, the more dominant is the right hemisphere. In condition 2, the same students are given the test again, only this time they are not hypnotized but are in their normal state of consciousness. The following scores are obtained. Student 1 2 3 4 5 6 7 8 9 10 11 12 Condition 1 20 16 22 18 23 30 16 19 14 16 17 25 Condition 2 14 13 17 19 21 22 14 22 12 14 15 22 The obtained probability = _________ A. 0.0161 B 0.0384 C 0.0192 D 0.0322
A random sample of 25 chemists from Washington state shows an average salary of $48123 with a standard deviation of $942. A random sample of 18 chemists from Florida state shows an average salary of $49603 with a standard deviation of $561. A chemist that has worked in both states believes that chemists in Washington make less than chemists in Florida. At a=0.05 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: Ο Η: μι μ2(claim) © Ho: μι 2 μ2 HA: M1 M₂(claim) O Ho: ₁ = ₂ HA: 12(claim) Since the level of significance is 0.05 the critical value is -1.684 (round to 3 places) The test statistic is: The p-value is: (round to 3 places)
2.4 Compute the 95% confidence interval for the population (true) value of prediction computed in question 2.3, and interpret it in words as well as graphically. The formula for the 95% confidence interval around a predicted Y value is: Y= Î±zerit(a=.05, 2 tailed)*sy.x Define and give the values for the following the terms in the formula. Î: 4.15504 Zsit: 0.025 Sy-x: 1.593 The numerical values for the confidence interval are:
When solar panels rated at 270 watts of power are manufactured, the power of the panels is not exactly 270 watts, but is Normally distributed with a mean of 270 watts and a standard deviation of 6.5 watts. When solar panels are connected together in series on a roof, the power generated is limited by the panel with the least power. For example, if three panels of 260 watts, 270 watts, and 280 watts are connected in series, the total power is NOT 260 + 270 + 280 = 810 watts. Instead, it is 3x260 = 780 watts (limited by the 260-watt panel). We need to connect seven panels together in series on a roof. What is the probability that the total power generated will be less than 1820 watts? Click here to view Table Z: The Normal Distribution (page 1). Click here to view Table Z: The Normal Distribution (page 2). The probability is O (Round to three decimal places as needed.)
A random sample of 23 chemists from Washington state shows an average salary of $45553 with a standard deviation of $877. A random sample of 19 chemists from Florida state shows an average salary of $44422 with a standard deviation of $571. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.05 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: O Ho: H1 µ2(claim) O Ho: H1 2 H2 HA: H1 < µ2(claim) O Ho:µ1 = µ2 HA: H1 + u2(claim) Since the level of significance is 0.05 the critical value is 2.024 and -2.024 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to reject the claim that…
In a random sample, 55 nurses who worked in the Covid-19 wing of a private hospital were interviewed, 10 indicated they were diagnosed with Covid-19 in 2020. When 50 nurses who do not work in the Covid-19 wing were selected at random, 8 indicated they were diagnosed with Covid-19 in 2020. Q.1.2.1 Calculate the standard deviation of the differences between the sample proportions of nurses who work in the Covid-19 wing and the sample proportions of nurses who do not work in the Covid-19 wing of the hospital. Q.1.2.2 Calculate the test statistic, z, of the differences between the sample proportions of nurses who work in the Covid-19 wing and the sample proportions of nurses who do not work in the Covid-19 wing of the hospital. Q.1.2.3 Find the probability that the sample proportions of nurses who work in the Covid-19 wing have higher chances of getting Covid-19 than sample
Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharged water is at most 150°F, there will be no negative effects on the river's ecosystem. To investigate whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above 150°, 50 water samples will be taken at randomly selected times and the temperature of each sample recorded. The resulting data will be used to test the hypotheses Ho: μ = 150° versus H₂: μ > 150°. In the context of this situation, describe type I error. a A type I error occurs when our estimate for the mean discharge temperature is higher than the actual temperature. A type I error occurs when we say that the plant is not in compliance when in fact it is. A type I error occurs when our estimate for the mean discharge temperature is lower than the actual temperature. A type I error occurs when we…
A newspaper article reported that people spends a mean of 6 hours per day watching tv, with a standard deviation of 1.8 hours. A psychologist would like to conduct interviews with the 15% of the population who spend the most time watching tv. She assumes that the daily time spent watching tv is normally distributed. At least how many hours of daily tv watching are necessary to be eligible for the interview? Carry intermediate computations to 4 places, and the answer to 1.
According to an investment firm, the average 401(k) account balance was $99,000 in 2017. To test if this average has recently changed, suppose a sample of 30 401(k) plans was recently selected, and it was found that the average 401(k) balance was $109,676. Assume that the population standard deviation is $27,452. Using α=0.02, complete parts a through d.
The brain volumes (cm³) of 20 brains have a mean of 1113.7 cm³ and a standard deviation of 128.9 cm³. Use the give standard deviation and the range rule of thumb to identify the limits separating values that are significantly low or significantly high. For such data, would a brain volume of 1361.5 cm³ be significantly high? 3 Significantly low values are cm³ or lower. (Type an integer or a decimal. Do not round.)
Suppose that the lifetimes of tires of a certain brand are normally distributed with a mean of 74,500 miles and a standard deviation of o miles. These tires come with a 55,000-mile warranty. The manufacturer of the tires can adjust o during the production process, but the adjustment of o is quite costly. The manufacturer wants to set ở once and for all so that only 1% of the tires will fail before warranty expires. Find the standard deviation to be set. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place. | miles Check esc -> @ 23 24 4. 5 6 1 2 y e tab w/
Two different researchers measured the weight of two separate samples of ruby-throated hummingbirds from the same population. Each calculated a 95% confidence interval for the mean weight of these birds. Researcher 1 found the 95% confidence interval to be 3.12 g < μ < 3.48 g while Researcher 2 found the 95% confidence interval to be 3.05g < μ < 3.62 g. Why would the two researchers get different answers? Which researcher most likely had the larger sample? Can you be certain about your answer in part (b)? Why or why not?

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