In 574 g of a binary substance of molecular formula MO2 there are 1.57 × 1025 oxygen atoms. Therefore, the mass of element M present, expressed in grams, is equal to Avogadro's constant: NA = 6.022 × 1023 mol-1?
In 574 g of a binary substance of molecular formula MO2 there are 1.57 × 1025 oxygen atoms. Therefore, the mass of element M present, expressed in grams, is equal to Avogadro's constant: NA = 6.022 × 1023 mol-1?
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In 574 g of a binary substance of molecular formula MO2 there are 1.57 × 1025 oxygen atoms. Therefore, the mass of element M present, expressed in grams, is equal to Avogadro's constant: NA = 6.022 × 1023 mol-1?
Expert Solution
Step 1
The given data contains,
mass of a binary substance = 574 g
Number of 'O' atoms = 1.57 x 1025
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