Implement two methods (using iterative and recursive approaches) to compute the sum of the reciprocals of the first n natural numbers. Mathematically, it can be denoted as follows: Sum(n) = 1 + 1/2 + 1/3+ ... +1/n Example 1: Input: [1] Output: [1.0] Explanation: n == 1, so sum(1)=1.0 Example 2: Input: [2] Output: [1.5] Explanation: n == 2, so sum(2)=1+1/2=1.5ˆ Iterative Approach: public static float sum_iterative (int n) { } Recursive Approach: Hint for recursive implementation: The prototype for the recursive approach should be as follows: Sum(n) ={1.0 ifn== 1 Sum(n−1) + 1/n if n >1 public static float sum_recursive (int n) { }

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