A hailstone sequence starts with some positive integer. If that integer is even, then you divide it by two to get the next integer in the sequence, but if it is odd, then you multiply it by three and add one to get the next integer in the sequence. Then you use the value you just generated to find the next value, according to the same rules. Fo example, if our initial number is 3, the subsequent numbers will be: 10, 5, 16, 8, 4, 2, 1. Write a function named hailstone that takes a positive integer parameter as the initial number of a hailstone sequence and returns how many steps it takes to reach 1 (technically you could keep going 1, 4, 2, 1, 4, 2, etc. but you will stop when you first reach 1). If the starting integer is 1, the return value should be 0, since it takes no steps to reach 1 (we're already there). For example, if the starting integer is 3, then the sequence would go: 3, 10, 5, 16, 8, 4, 2, 1, and the return value should be 7, since took 7 steps to reach 1. Your function does not need to print anything out - just return a value. For example, your function could be used like this: answer = hailstone(1000) print(answer) You cannot use recursion, since we haven't covered that technique. That means that for this assignment you cannot have your function call itself. This includes indirect recursion, such as one function calling a second function that calls the first function. The file must be named: hailstone.py

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