For example,countPaths (0, 0, 2, 2) returns 6countPaths (0, 0, 1, 1) returns 2countPaths(2, 1, 2, 2) returns 1Hint! Find first the base case(s). The examples above will be useful. Then, think about how toreduce the path length by 1 for recursive call(s). For example, one possibility to reach (2, 2) is toreach first (1, 2) and make right move. countPaths can be used to count paths to reach (1, 2).A large penalty will be applied to non recursive solutions. Hardcoding will always get zero point.static int countPaths (int x1, int y1, int x2, int y2){ Consider a grid of size (x, y) where x and y are positive integers. The following figureshows an example grid of size (2,3) and two points p1 and p2 in the grid. Assume that x andy of p2 is greater than x and y of p1.p2(2,2)ectangular Snipp1(0,0)Write a recursive method named countPaths that returns the number of distinct shortest pathsfrom p1 to p2. The method takes 4 ints as the parameters – i.e., x and y values of the twopoints: x1, y1, x2, and y2. Note that you do not need to print the paths. Count only.To be shortest, a path will only consist of only upward and rightward movements where eachmovement increases x- or y-coordinate value by 1. In the figure above,|(right, up, right, up) or (right, right, up, up) are both shortest paths from p1 to p2.For example,countPaths (0, 0, 2, 2) returns 6countPaths (0, 0, 1, 1) returns 2countPaths (2, 1, 2, 2) returns 1

C++ Code:As the specification mentioned above in the code , the required C++ Code to calculate…

countPaths(0, 0, 2, 2) returns 6 countPaths (0, 0, 1, 1) returns 2 countPaths (2, 1, 2, 2) returns 1 Hint! Find first the base case(s). The examples above will be useful. Then, think about how to educe the path length by 1 for recursive call(s). For example, one possibility to reach (2, 2) is to each first (1, 2) and make right move. countPaths can be used to count paths to reach (1, 2).

countPaths(0, 0, 2, 2) returns 6 countPaths (0, 0, 1, 1) returns 2 countPaths (2, 1, 2, 2) returns 1 Hint! Find first the base case(s). The examples above will be useful. Then, think about how to educe the path length by 1 for recursive call(s). For example, one possibility to reach (2, 2) is to each first (1, 2) and make right move. countPaths can be used to count paths to reach (1, 2).

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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