this is a python code use the code provided and fill in the # lines with new & understandable code. Implement the quadratic_formula) function. The function takes 3 arguments, a, b, and e, and computes the two results of the quadraticformula:-b+ v - dae2a-6 - V - dae2aThe quadratic_formula() function returns the tuple (x1, x2). Ex: When a = 1, b = -5, and c = 6, quadratic_formula() retums (3, 2).Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a floatand passed to the quadratic.formula() function.Ex: If the input is2 -3 -77the output is:Solutions to 2x*2 +-3x + -77 = 0xl-7x2 - -5.50# TODO: Import math moduledef quadratic_formula (a, b, c) :# TODO: Compute the quadratic formula results in variables x1 and x2return (x1, x2)def print_number (number, prefix_str):if float (int (number)) =- number:print (f'(prefix_str}{number:.0f}')else:print (f'(prefix_str}{number: .2f}')ifinput_line -split_line - input_line.split (" ")a - float (split_line [0])b - float (split_line[1])c - float (split_line[2])solution = quadratic_formula (a, b, c)print (f'Solutions to (a:.0f}x^2 + {b:.0f}x + {c:.0f} = 0')print_number (solution(0], 'x1 = ')print_number (solution [1], 'x2 = ')namemain":input ()

Hey. The answer to above question has been attached in step 2. Please note that split_line isn't…

Implement the quadratic_formula) function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic formula -b+ V - 4ac 2a --b- dac 2a The quadratic formula) function returns the tuple (x1, x2). Ex: When a = 1, b=-5, and e = 6, quadratic formula) retuns (3, 2). Code provided in main py reads a single input line containing values for a, b, and a, separated by spaces. Each input is converted to a float and passed to the quadratic.formula) function Ex: If the input is 2 -3 -77 the autput is: Solutions to 2x*2 + -3x + -77-0 xl -7 x2 - -5.50 - TODO: Import math module def quadratic_formula (a, b, c): # TODO: Compute the quadratic formula results in variables x1 and x2 return (x1, x2) def print_number (number, prefix_str): if float (int (number)) -- number: print (f'(prefix_str}{number:.0f}') else: print (f'(prefix_str}{number:.2f}') if main ": name Înput_line - input () split_line - input_line.split (" ") a - float (split_line[0]) b - float (split_line[1]) c - float (split_line[2]) solution - quadratic_formula (a, b, c) print (f'Solutions to (a:.0f}x^2 + {b:.0f}x + {c:.0f} - 0') print_number (solution(0], 'xl - ') print_number (solution [1], 'x2 - ')

Implement the quadratic_formula) function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic formula -b+ V - 4ac 2a --b- dac 2a The quadratic formula) function returns the tuple (x1, x2). Ex: When a = 1, b=-5, and e = 6, quadratic formula) retuns (3, 2). Code provided in main py reads a single input line containing values for a, b, and a, separated by spaces. Each input is converted to a float and passed to the quadratic.formula) function Ex: If the input is 2 -3 -77 the autput is: Solutions to 2x*2 + -3x + -77-0 xl -7 x2 - -5.50 - TODO: Import math module def quadratic_formula (a, b, c): # TODO: Compute the quadratic formula results in variables x1 and x2 return (x1, x2) def print_number (number, prefix_str): if float (int (number)) -- number: print (f'(prefix_str}{number:.0f}') else: print (f'(prefix_str}{number:.2f}') if main ": name Înput_line - input () split_line - input_line.split (" ") a - float (split_line[0]) b - float (split_line[1]) c - float (split_line[2]) solution - quadratic_formula (a, b, c) print (f'Solutions to (a:.0f}x^2 + {b:.0f}x + {c:.0f} - 0') print_number (solution(0], 'xl - ') print_number (solution [1], 'x2 - ')

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

this is a python code use the code provided and fill in the # lines with new & understandable code.

Implement the quadratic_formula) function. The function takes 3 arguments, a, b, and e, and computes the two results of the quadratic
formula:
-b+ v - dae
2a
-6 - V - dae
2a
The quadratic_formula() function returns the tuple (x1, x2). Ex: When a = 1, b = -5, and c = 6, quadratic_formula() retums (3, 2).
Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a float
and passed to the quadratic.formula() function.
Ex: If the input is
2 -3 -77
the output is:
Solutions to 2x*2 +-3x + -77 = 0
xl-7
x2 - -5.50
# TODO: Import math module
def quadratic_formula (a, b, c) :
# TODO: Compute the quadratic formula results in variables x1 and x2
return (x1, x2)
def print_number (number, prefix_str):
if float (int (number)) =- number:
print (f'(prefix_str}{number:.0f}')
else:
print (f'(prefix_str}{number: .2f}')
if
input_line -
split_line - input_line.split (" ")
a - float (split_line [0])
b - float (split_line[1])
c - float (split_line[2])
solution = quadratic_formula (a, b, c)
print (f'Solutions to (a:.0f}x^2 + {b:.0f}x + {c:.0f} = 0')
print_number (solution(0], 'x1 = ')
print_number (solution [1], 'x2 = ')
name
main
":
input ()

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