Implement the Point default constructor by using the initializer list. point.cpp 1 #include "point.h" 3 Point::Point() 4 { // body is empty } 6.
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![Implement the Point default constructor by using the initializer list.
point.cpp
1
#include "point.h"
3
Point::Point()
4
{
// body is empty
6 }
point.h
1
#ifndef POINT H
2
#define POINT H
3
4
class Point
{
public:
Point();
private:
int m_x;
int m_y;
};
// 0,0
8
9
10
11
12
13
#endif
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- In Java please help with the following: Sees whether this list is empty.@return True if the list is empty, or false if not. */ public boolean isEmpty(); } // end ListInterface Hint:Node class definition should look something like: public class Node<T> { T element; Node next; Node prev; public Node(T element, Node next, Node prev) { this.element = element;this.next = next;this.prev = prev; } }typedef struct node_t node_t; struct node_t { }; int32_t value; node_t* next; node_t* insert (node_t* list, int32_t v, int32_t* flag); 3) As you may have noticed from MT1, Howie is lazy. He wants you to write the interface for the following implementation of function copy_to_linked_list. He really appreciates your help! /* copy_to_linked_list int32_t copy_to_linked_list (int32_t a[], int32_t size, node_t** list_p) { int32_t flag, i; for (i = 0; i < size; ++i) { *list_p = insert (*list_p, a[i], &flag); if (-1== flag) return -1; } return 0;11. Given the following list, trace the given code and draw the list afterward. SHOW YOUR WORK. head "chair" "table" "door" "sofa" "wall" "window" "floor" LLNode Ruli int temp; head; head.getLink (); while (q != null) { RitetInfo () ; RisetInfo (g.getInfo()); AetInfo (temp); LgetLink (); Aetlink (RgetLink()); a = temp = d AigetLink () ; if (p != null) RigetLink (); g = }
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- Complete the Kennel class by implementing the following methods: addDog(Dog dog) findYoungestDog() method, which returns the Dog object with the lowest age in the kennel. Assume that no two dogs have the same age. Given classes: Class LabProgram contains the main method for testing the program. Class Kennel represents a kennel, which contains an array of Dog objects as a dog list. (Type your code in here.) Class Dog represents a dog, which has three fields: name, breed, and age. (Hint: getAge() returns a dog's age.) For testing purposes, different dog values will be used. Ex. For the following dogs: Rex Labrador 3.5 Fido Healer 2.0 Snoopy Beagle 3.2 Benji Spaniel 3.9 the output is: Youngest Dog: Fido (Healer) (Age: 2.0)Add the following functions and write a program to test these functions in the class linkedListType: a. Write the definition of a function that returns the data of the kth element of the linked list. If such element is not exist in the list, exit the program. b. Write the definition of a function that deletes the kth element of the linked list. If such element does not exist in the list, exit the program and display message as output.1.Assume some Node class with info link fields . Complete this method in class List that returns a reference to the node containing the data item in the argument findThis, Assume that findThis is in the list public class list { protected Node head ; Protected int size ; Public Node find (char find this) { Node curr = head; while(curr != null) { if(curr.info == findThis) return curr; curr = curr.link; } return -1; } }
- @6 The Reference-based Linked Lists: Select all of the following statements that are true. options: As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions. According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node. According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node. In a double-ended singly linked list, the tail reference variable provides access to the entire list. In a circular linked list, the last node references the first node.Having trouble with creating the InsertAtEnd function in the ItemNode.h file below. " // TODO: Define InsertAtEnd() function that inserts a node // to the end of the linked list" Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts ------------------------------------------------------- main.cpp -------------------------------------------------------- #include "ItemNode.h" int main() { ItemNode *headNode; // Create intNode objects ItemNode *currNode; ItemNode *lastNode; string item; int i; int input; // Front of nodes list headNode = new ItemNode(); lastNode = headNode; cin >> input; for (i = 0; i < input; i++) { cin >> item;…In C++ I need to write a recursive function insertEnd that will call a recursive method insertEnd(const ItemType& newEntry, Node<ItemType>* node), to insert newEntry at the end of the linked list I completely stuck and can't figure out where the error is coming from. main #include <iostream> #include "LinkedList.cpp" int main() { Node<int>* first = new Node(1); Node<int>* second = new Node(2); Node<int>* third = new Node(3); first->next = second; second->next = third; cout<<first->data<<endl; cout<<first->next->data<<endl; cout<<first->next->next->data<<endl; LinkedList<int> list; //an empty linked list for(int i =0; i<10; i++){ list.inserEnd(i); list.display(); } return 0; } linkedlist.cpp #include "LinkedList.h" #include "iostream" using namespace std; template <class T> LinkedList<T>::LinkedList(){ head = nullptr; } template <class…
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