COMPLETE THIS CODE and make sure it passes all the test cases. // EXERCISE 4.1 MYLIST ITERATIVE CATENATE MUTATE /** * Catenate two MyLists, listA and listB. Mutate listA. * @param listA is a MyList object. * @param listB is a MyList object. * @return a list consisting of the elements of listA followed by the * elements of listB. */ public static MyList iterCatMutList(MyList listA, MyList listB) { }
COMPLETE THIS CODE and make sure it passes all the test cases. // EXERCISE 4.1 MYLIST ITERATIVE CATENATE MUTATE /** * Catenate two MyLists, listA and listB. Mutate listA. * @param listA is a MyList object. * @param listB is a MyList object. * @return a list consisting of the elements of listA followed by the * elements of listB. */ public static MyList iterCatMutList(MyList listA, MyList listB) { }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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COMPLETE THIS CODE and make sure it passes all the test cases.
// EXERCISE 4.1 MYLIST ITERATIVE CATENATE MUTATE
/**
* Catenate two MyLists, listA and listB. Mutate listA.
* @param listA is a MyList object.
* @param listB is a MyList object.
* @return a list consisting of the elements of listA followed by the
* elements of listB.
*/
public static MyList iterCatMutList(MyList listA, MyList listB) {
}
![Complete the method MyList iterCatMutlist (MyList listA, MyList 1istB) iteratively, to return a list
consisting of all elements of listA, followed by all elements of listB.
The method modifies/mutates listA so that it is concatenated with listB.
Use loops.
Test case 1:
[1, 2, 3],
MyList.iterCatMutlist (list1, list2);
list1
list2
[4, 5, 6]
list
list
[1, 2, 3, 4, 5, 6]
list1 → [1, 2, 3, 4, 5, 6]
For example:
Test
Result
My List list1 = MyList.ofEntries (1, 2, 3);
[1, 2, 3, 4, 5, б]
MyList list2 = MyList.ofEntries(4, 5, 6);
[1, 2, 3, 4, 5, 6]
MyList list = MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
MyList list1
MyList.ofEntries();
null
My List list2 = MyList.ofEntries ();
null
MyList list
MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
MyList list1
MyList.ofEntries(5);
[5]
My List list2
MyList.ofEntries();
[5]
%3D
MyList list
MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
My List list1
My List list2
MyList.ofEntries();
[5]
%3D
MyList.ofEntries(5);
null
MyList list = MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7933b4d7-dfbc-452b-bf78-981e959f7b6a%2F1498aea5-d85a-47b8-acd8-3f6a2d4ae416%2F2os07kg_processed.png&w=3840&q=75)
Transcribed Image Text:Complete the method MyList iterCatMutlist (MyList listA, MyList 1istB) iteratively, to return a list
consisting of all elements of listA, followed by all elements of listB.
The method modifies/mutates listA so that it is concatenated with listB.
Use loops.
Test case 1:
[1, 2, 3],
MyList.iterCatMutlist (list1, list2);
list1
list2
[4, 5, 6]
list
list
[1, 2, 3, 4, 5, 6]
list1 → [1, 2, 3, 4, 5, 6]
For example:
Test
Result
My List list1 = MyList.ofEntries (1, 2, 3);
[1, 2, 3, 4, 5, б]
MyList list2 = MyList.ofEntries(4, 5, 6);
[1, 2, 3, 4, 5, 6]
MyList list = MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
MyList list1
MyList.ofEntries();
null
My List list2 = MyList.ofEntries ();
null
MyList list
MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
MyList list1
MyList.ofEntries(5);
[5]
My List list2
MyList.ofEntries();
[5]
%3D
MyList list
MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
My List list1
My List list2
MyList.ofEntries();
[5]
%3D
MyList.ofEntries(5);
null
MyList list = MyList.iterCatMutlist(list1, list2);
System.out.println(list);
System.out.println(list1);
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