Implement the line below in Java. bel' (i) = bel(i – 2) x 0.25 + bel(i – 1) x 0.5 + bel(i) × 0.25; To make things easier, here is a faulty implementation, so you can have a look. public static double discreteFilter(float bel, float move){ float bel prime = (bel(i-2) * 0.25) + (bel(i-1) * 0.5) + (bel(i)*0.25); %3D return 0; Thanks
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- Write a program in Java for the below situation In a royal casino, there is a lottery at 14 number card. If a person is playing that game, find the probability of his winnings. if we have array of all cards = %3D {1,2,014,78,90,56,105,789,43,89,56,90,123,71,101,51, 134,0,4,12,0,6,54,98,54)Please fix errors for the java code below. The program is a t square fractal (image below) import javax.swing.*;import java.awt.*;import java.awt.geom.*; //main classpublic class SquareFractal { public static void main(String[] args) { FractalFrame tframe = new FractalFrame(); tframe.setTitle("T Square Fractal"); tframe.setVisible(true); }} //JFrame extended in fractal class class T_Fractal extends JFrame{ private JPanel panel; private int twidth, theight; private int x = 200; private int limit = 15; public T_Fractal() { setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); //default height and width final int Width = 1000; final int Height = 1000; setSize(Width, Height); setLocation(200,50); panel = new JPanel(); Container t_content = getContentPane(); t_content.add(panel, "Center"); } public void paint(Graphics graphics) { super.paint(graphics); Graphics2D g2 = (Graphics2D) graphics; twidth = getWidth(); theight = getHeight();…Implement an ADT that can used as a Tic-Tac-Toe game board. Your ADT will implement the interface given below. In the main method also include a simple usage example.Here are the rules of N x N Tic-Tac-Toe game:• Players take turns placing characters into empty squares (" ").• The first player A always places "X" characters, while the second player B always places "O" characters.• "X" and "O" characters are always placed into empty squares, never on filled ones.• The game ends when there are N of the same (non-empty) character filling any row, column, or diagonal.• The game also ends if all squares are non-empty.• No more moves can be played if the game is over
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- Write a second convertToInches() with two double parameters, numFeet and numInches, that returns the total number of inches. Ex: convertToInches(4.0, 6.0) returns 54.0 (from 4.0 * 12 + 6.0). import java.util.Scanner; public class FunctionOverloadToInches { public static double convertToInches(double numFeet) {return numFeet * 12.0;} /* Your solution goes here */ public static void main (String [] args) {double totInches; totInches = convertToInches(4.0, 6.0);System.out.println("4.0, 6.0 yields " + totInches); totInches = convertToInches(5.8);System.out.println("5.8 yields " + totInches);}}Implement the Board class. Make sure to read through those comments so that you know what is required. package p1; // You need a random number generator in order to make random moves. Use rand below private static final Random rand = new Random(); private byte[][] board; /** * Construct a puzzle board by beginning with a solved board and then * making a number of random moves. Note that making random moves * could result in the board being solved. * * @param moves the number of moves to make when generating the board. */ public Board(int moves) { // TODO } /** * Construct a puzzle board using a 2D array of bytes to indicate the contents * of the cells in the triangle. * * @param b a "triangular array" with 5 rows where row 0 has 1 * cell, row 1 has 2 cells, etc. */ public Board(byte[][] b) { board = Arrays.copyOf(b, b.length); } public void printBoard() { for (int i = 0; i < board.length; i++) { for (int j = 0; j < board[i].length; j++) {…In java Implement a public static double[] ageMetrics(Patient[] patients) method that returns an array of length 3 with the following three values (starting at index 0): The age of the youngest patient The age of the oldest patient The mean age of all patients
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