Implement a sort method public void sort() Implement any sort algorithm. Do not use any of Java's built-in sorting algorithms. i have this code so far: import java.util.AbstractList; import java.util.Random; public class MyLinkedList> extends AbstractList { int size = 0; Node root = null; class Node { E elem; Node next; public Node(E elem) { this.elem = elem; next = null; } } @Override public void add(int index, E element) { Node newNode = new Node(element); Node temp = root; for (int i = 1; i < index; i++) { temp = temp.next; } if ((temp == null) || (index == 0)) { newNode.next = root; root = newNode; } else { newNode.next = temp.next; temp.next = newNode; } size++; } @Override public E remove(int index) { E result = null; Node temp = root; for (int i = 1; i < index; i++) { temp = temp.next; } if (root == null) { result = null; } else if ((temp == null) || (index == 0)) { result = root.elem; root = root.next; } else { result = temp.next.elem; temp.next = temp.next.next; } size--; return result; } @Override public E set(int index, E element) { E replaced = remove(index); add(index, element); return replaced; } @Override public E get(int index) { Node temp = root; for (int i = 0; i < index; i++) { if (temp != null) { temp = temp.next; } else { return null; } } if (temp != null) { return temp.elem; } return null; } @Override public int size() { return size; } public void shuffle(long seed) { Random random = new Random(seed); Node temp = root; while (temp != null) { int index = random.nextInt(size); E data = temp.elem; temp.elem = get(index); set(index, data); temp = temp.next; } } public void sort() { for (int i = 0; i < size; i++) { for (int j = 0; j < size - 1 - i; j++) { E elem1 = get(j); E elem2 = get(j + 1); if (elem1.compareTo(elem2) > 0) { set(j, elem2); set(j + 1, elem1); } } } } } however i am having trouble with my output i.e. it is supposed to be Small data set\n [E, A, D, B, C]\n Sort\n [A, B, C, D, E]\n Clearing\n [ ]\n // two spaces here ... but it is outputting: Small data set\n [E, A, D, B, C]\n Sort\n [A, B, C, D, E]\n Clearing\n [ ]\n // only one space ... can an expert help fix my code so that it creates two spaces in the brackets of the clearing, that is the only part of my ouput that is incorrect

Implement a sort method public void sort() Implement any sort algorithm. Do not use any of Java's built-in sorting algorithms. i have this code so far: import java.util.AbstractList; import java.util.Random; public class MyLinkedList> extends AbstractList { int size = 0; Node root = null; class Node { E elem; Node next; public Node(E elem) { this.elem = elem; next = null; } } @Override public void add(int index, E element) { Node newNode = new Node(element); Node temp = root; for (int i = 1; i < index; i++) { temp = temp.next; } if ((temp == null) || (index == 0)) { newNode.next = root; root = newNode; } else { newNode.next = temp.next; temp.next = newNode; } size++; } @Override public E remove(int index) { E result = null; Node temp = root; for (int i = 1; i < index; i++) { temp = temp.next; } if (root == null) { result = null; } else if ((temp == null) || (index == 0)) { result = root.elem; root = root.next; } else { result = temp.next.elem; temp.next = temp.next.next; } size--; return result; } @Override public E set(int index, E element) { E replaced = remove(index); add(index, element); return replaced; } @Override public E get(int index) { Node temp = root; for (int i = 0; i < index; i++) { if (temp != null) { temp = temp.next; } else { return null; } } if (temp != null) { return temp.elem; } return null; } @Override public int size() { return size; } public void shuffle(long seed) { Random random = new Random(seed); Node temp = root; while (temp != null) { int index = random.nextInt(size); E data = temp.elem; temp.elem = get(index); set(index, data); temp = temp.next; } } public void sort() { for (int i = 0; i < size; i++) { for (int j = 0; j < size - 1 - i; j++) { E elem1 = get(j); E elem2 = get(j + 1); if (elem1.compareTo(elem2) > 0) { set(j, elem2); set(j + 1, elem1); } } } } } however i am having trouble with my output i.e. it is supposed to be Small data set\n [E, A, D, B, C]\n Sort\n [A, B, C, D, E]\n Clearing\n [ ]\n // two spaces here ... but it is outputting: Small data set\n [E, A, D, B, C]\n Sort\n [A, B, C, D, E]\n Clearing\n [ ]\n // only one space ... can an expert help fix my code so that it creates two spaces in the brackets of the clearing, that is the only part of my ouput that is incorrect

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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

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Question

Implement a sort method

public void sort()

Implement any sort algorithm. Do not use any of Java's built-in sorting algorithms.

i have this code so far:

import java.util.AbstractList;
import java.util.Random;

public class MyLinkedList<E extends Comparable<E>> extends AbstractList<E> {

int size = 0;
Node<E> root = null;

class Node<E> {

E elem;
Node<E> next;

public Node(E elem) {
this.elem = elem;
next = null;
}
}

@Override
public void add(int index, E element) {

Node<E> newNode = new Node(element);

Node<E> temp = root;

for (int i = 1; i < index; i++) {
temp = temp.next;
}

if ((temp == null) || (index == 0)) {

newNode.next = root;
root = newNode;

} else {

newNode.next = temp.next;
temp.next = newNode;

}

size++;

}

@Override
public E remove(int index) {

E result = null;

Node<E> temp = root;

for (int i = 1; i < index; i++) {
temp = temp.next;
}

if (root == null) {
result = null;

} else if ((temp == null) || (index == 0)) {

result = root.elem;
root = root.next;

} else {

result = temp.next.elem;
temp.next = temp.next.next;

}

size--;

return result;

}

@Override
public E set(int index, E element) {

E replaced = remove(index);
add(index, element);

return replaced;
}

@Override
public E get(int index) {

Node<E> temp = root;

for (int i = 0; i < index; i++) {
if (temp != null) {
temp = temp.next;
} else {
return null;
}
}

if (temp != null) {
return temp.elem;
}

return null;
}

@Override
public int size() {
return size;
}

public void shuffle(long seed) {

Random random = new Random(seed);

Node<E> temp = root;

while (temp != null) {

int index = random.nextInt(size);

E data = temp.elem;

temp.elem = get(index);
set(index, data);

temp = temp.next;
}
}

public void sort() {

for (int i = 0; i < size; i++) {
for (int j = 0; j < size - 1 - i; j++) {

E elem1 = get(j);
E elem2 = get(j + 1);

if (elem1.compareTo(elem2) > 0) {
set(j, elem2);
set(j + 1, elem1);
}
}
}
}
}

however i am having trouble with my output i.e.

it is supposed to be

Small data set\n
[E, A, D, B, C]\n
Sort\n
[A, B, C, D, E]\n
Clearing\n
[ ]\n // two spaces here ...

but it is outputting:

Small data set\n
[E, A, D, B, C]\n
Sort\n
[A, B, C, D, E]\n
Clearing\n
[ ]\n // only one space ...

can an expert help fix my code so that it creates two spaces in the brackets of the clearing, that is the only part of my ouput that is incorrect

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