(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) Ca(g) AHat = +190 kJ/mol Ca(g) Ca, (g) + 2e AHE = +1730 kJ/mol C2(g) 2CI(g) AHat = +121 kJ/mol Ca2*(g) + 2CI(g) CaCl2(s) AHLE = -2184 kJ/mol Ca(s) + Cl2(g) – CaCl2(s) AHĘ = -795 kJ/mol

(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) Ca(g) AHat = +190 kJ/mol Ca(g) Ca, (g) + 2e AHE = +1730 kJ/mol C2(g) 2CI(g) AHat = +121 kJ/mol Ca2*(g) + 2CI(g) CaCl2(s) AHLE = -2184 kJ/mol Ca(s) + Cl2(g) – CaCl2(s) AHĘ = -795 kJ/mol

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter5: Electron Configurations And The Periodic Table

Section: Chapter Questions

Problem 116QRT

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Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) Ca(g) DHat = +190 kJ/mol Ca(g) Ca2+(g) + 2e- DHIE = +1730 kJ/mol Cl2(g) 2Cl(g) DHat = +121 kJ/mol Ca2+(g) + 2Cl-(g) CaCl2(s) DHLE = -2184 kJ/mol Ca(s) + Cl2(g) CaCl2(s) DHF = -795 kJ/mol
Which of the following reactions represents an electron gain energy that would be positive (i.e. endothermic). O(g) → O+(g) + e- Ne(g) + e- → Ne-(g) O(g) + e- → O-(g) I(g) → I+(g) + e- I(g) + e- → I-(g) Ne(g) → Ne+(g)+ e- fast plz
Of the five elements Sn, Si, Sb, O, Te, which has the most endothermic reaction? (E represents an atom.) What name is given to the energy for the reaction? E(g) ⟶ E+(g) + e−
Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to (ii) calculate the electron affinity of chlorine: DHat = +190 kJ/mol Ca(s) Ca(g) Ca2* (9) 2е- DHJE = +1730 kJ/mol + Ca(g) 2Clg) DHat = +121 kJ/mol Cl2(g) CaCl2(s) DHLE = -2184 kJ/mol Ca2+, 2Cl (g) + *(9) CaCl2(s) DHF = -795 kJ/mol Ca(s) + Cl2(g)
Use the following data and the Born-Haber cycle to calculate the first ionization energy (ΔH IE1) of K(g) K(s) → K(g) 89 kJ mol-1 Cl(g) + e– → Cl–(g) -349 kJ mol-1 K(s) + ½ Cl2(g) → KCl(s) -437 kJ mol-1 K(g) → K+(g) + e– ΔH IE1 Cl2(g) → 2Cl(g) 244 kJ mol-1 K+(g) + Cl–(g) → KCl(s) -717 kJ mol-1 Use the bond energies listed in the table below to estimate the standard enthalpy of the reaction: CCl3CHCl2(g) + 2HF(g) → CCl3CHF2(g) + 2HCl(g) C – H 412 kJ mol-1 C – C 348 kJ mol-1 C – Cl 338 kJ mol-1 H – Cl 431 kJ mol-1 C – F 484 kJ mol-1 H – F 565 kJ mol-1
Use the following data and the Born-Haber cycle to calculate the first ionization energy (ΔH IE1) of K(g) K(s) → K(g) 89 kJ mol-1 Cl(g) + e– → Cl–(g) -349 kJ mol-1 K(s) + ½ Cl2(g) → KCl(s) -437 kJ mol-1 K(g) → K+(g) + e– ΔH IE1 Cl2(g) → 2Cl(g) 244 kJ mol-1 K+(g) + Cl–(g) → KCl(s) -717 kJ mol-1
Draw a Born-Haber cycle for the formation of NaH(s) from its elements. Drag the appropriate labels to their respective targets. 1/2H2 (g) → H(g)+218 kJ/mol Na(g) → Na+ (g) +e +495.8 kJ/mol H(g) +e → H (g) -72.8 kJ/mol Na (g) + H (g) → NaH(s) -808 kJ/mol Na(s) → Na(g)+107.3 kJ/mol Na(s) +1/2H2(g) → NaH(s) -60 kJ/mol
Please answer this
Hess's Law 2. The data provided below is used to construct a Born-Haber Cycle for Magnesium Fluoride. Chemical Formula of Reaction → Mg (s) + F2 (g) MgF2 (s) Mg (s) Mg (g) Name of Reaction Enthalpy of Formation Atomization Energy AH of Reaction -1124 kJ/mol 148 kJ/mol -> Mg (g) → Mg (g) First Ionization Energy 738 kJ/mol Mg (g) Mg2+ (g) Second Ionization Energy 1451 kJ/mol F2 (g) 2F (g) Bond Dissociation Energy 318 kJ/mol F (g) F (g) Electron Affinity -328 kJ/mol The lattice energy of Magnesium Fluoride can be calculated using the balanced chemical equations below: Mg (g)+2F (g) → MgF: (s) AH = Lattice Energy What is the lattice energy of magnesium fluoride? ni berfomb sa bios my
Use the data given below to construct a Born-Haber cycle to determine the electron affinity of Br. ΔH°(kJ mol-1) K(s) → K(g) 89 K(g) → K⁺(g) + e⁻ 419 Br2(l) → 2Br(g) 193 K(s) + ½Br2(g) → KBr (s) -394 KBr(s) → K⁺(g) + Br⁻(g) 674 A) -885 kJ B) -464 kJ C) +367 kJ D) -325 kJ E) +246 kJ
4. Write out the 15 microstates of O in a table and then group them into 3 atomic terms. Which term has the lowest energy? Determine the order in energy of levels in this lowest-energy term. The atomic terms and the lowest-energy term of O are exactly same as those of C. The order in energy of the three atomic terms is: 3p < 'D< !S However, the order in energy of levels of O is the opposite of that of C. The order of the energy levels of the lowest-energy term ³P is: ³P2 < ³P1 < ³Po
The quantum numbers for the electron(s) in the valence shell of thallium (81TI) are: NOTE: the designation electron(s) with brackets around the s means that there might be only one: "electron" or there might be more than one: "electrons" O (6,1,-1,2) (6,1,0,½) (6,1,1,½) O (6,1,-1,12) O (6,0,0,±12) (6,1,-1,½) O (6,0,0,±½/2)

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