Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to (ii) calculate the electron affinity of chlorine: DHạt = +190 kJ/mol Ca(s) Ca(g) DHE = +1730 kJ/mol + 2е- Ca(g) Ca2+, (g) DHat = +121 kJ/mol Cl2(g) 2C(g) CaCl2(s) DHLE = -2184 kJ/mol Ca2* (g) 2CF (g) + DHF = -795 kJ/mol Cl2(g) CaCl2(s) Ca(s) +

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Please could someone help me solve this without using Hess's Law and using upward arrows for positive energy changes and downwards arrows for negative energy changes 

Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to
(ii)
calculate the electron affinity of chlorine:
DHạt
= +190 kJ/mol
Ca(g)
Ca(s)
2e-
DHJE = +1730 kJ/mol
Ca2* (g)
+
Ca(g)
DHạt = +121 kJ/mol
Cl2(g)
2Cl(g)
DHLE
= -2184 kJ/mol
Ca2* (g)
2C1 (9)
CaCl2(s)
+
CaCl2(s)
DHF = -795 kJ/mol
Ca(s)
Cl2(g)
+
Transcribed Image Text:Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to (ii) calculate the electron affinity of chlorine: DHạt = +190 kJ/mol Ca(g) Ca(s) 2e- DHJE = +1730 kJ/mol Ca2* (g) + Ca(g) DHạt = +121 kJ/mol Cl2(g) 2Cl(g) DHLE = -2184 kJ/mol Ca2* (g) 2C1 (9) CaCl2(s) + CaCl2(s) DHF = -795 kJ/mol Ca(s) Cl2(g) +
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