If you shine light on a conducting metallic surface, the light can impart energy to electrons in the conductor, potentially freeing them from the surface if the energy is higher than the so-called "work function", which is the energy required to free the electron from the surface. If you place another conducting surface in a position at which it can catch these electrons, and connect these two conductors by another conductor such as a wire, you can generate a so-called photoelectric current. Suppose the work function of a particular metal is 4.8 x 10-19 J. If light can impart an energy of 14.4 x 10-19 J to each electron, what must be the potential difference of the two conducting surfaces in order to stop a photoelectric current? Which conducting surface should be at the higher potential?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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If you shine light on a conducting metallic surface, the light can impart energy to electrons in the conductor, potentially freeing them from the surface if the energy is higher than the so-called "work function", which is the energy required to free the electron from the surface. If you place another conducting surface in a position at which it can catch these electrons, and connect these two conductors by another conductor such as a wire, you can generate a so-called photoelectric current. Suppose the work function of a particular metal is 4.8 x 10-19 J. If light can impart an energy of 14.4 x 10-19 J to each electron, what must be the potential difference of the two conducting surfaces in order to stop a photoelectric current? Which conducting surface should be at the higher potential?

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