A light source emitting radiation at 7.00 x 10¹4 Hz is incapable of ejecting photoelectrons from a certain metal. In an attempt to use this source to eject photoelectrons from the metal, the source is given a velocity toward the metal. b) When the speed of the light source is equal to 0.280c, photoelectrons just begin to be ejected from the metal. What is the work function of the metal?
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- The mathematical equation for studying the photoelectric effect is hν = W + 1/2 meu2 where ν is the frequency of light shining on the metal; W is the energy needed to remove an electron from the metal; and me and u are the mass and speed of the ejected electron, respectively. In an experiment, a student found that a maximum wavelength of 351 nm is needed to just dislodge electrons from a metal surface. Calculate the velocity (in m/s) of an ejected electron when the student employed light with a wavelength of 283 nm.Considering the photoelectric effect, if a liberated photoelectron has a maximum kinetic energy of 0.211 eV when light with a wavelength of 450 nm is being used, what is the work function of the material measured in eV? 1 eV = 1.602 x 10-19 JYou set up a photoelectric experiment with an unknown metal to eject electrons. You use light of wavelength λ = 670 nm, which just BARELY ejects electrons from the metal. Planck□s constant is either h = 6.63 x 10-34 J-s or h = 4.14 x 10-15 ev.s. a) What is the binding energy of the unknown metal in eV? ev b) You change the light source to one with a wavelength of λ = 310 nm. Using the binding energy you found in the previous step, find the maximum kinetic energy of an electron that is ejected from the metal in Joules. J c) What is the stopping voltage for an electron with the kinetic energy you just found? V
- UV radiation having a wavelength of 146 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case.Ultraviolet light with a single wavelength and with an intensity of 550 W/m² is incident normally on the surface of a metal that has a work function of 3.44 eV. Photoelectrons are emitted with a maximum speed of 420 km/s. Find the maximum possible rate of photoelectron emission from 1 cm² of the surface by imagining that every photon produces one photoelectron.Light with a frequency of (1.99x10^15) Hz hits a metal with a work function of (4.200x10^0) eV. Determine the maximum velocity of photoelectrons generated by this setup.
- The momentum of light, as it is for particles, is exactly reversed when a photon is reflected straight back from a mirror, assuming negligible recoil of the mirror. The change in momentum is twice the photon’s incident momentum, as it is for the particles. Suppose that a beam of light has an intensity I and falls on an area A of a mirror and reflects from it. Er = I A t p = 2 ( I A t )/c Use Newton’s second law to write an equation for the force on the mirror for time t. Use the variables along with c for the speed of light.s) The cutoff frequency of a specific metal is known to be 0.72x1015Hz. During a photoelectric experiment, 3.7x102º photons with a wavelength of 167nm are striking a plate every second. What is the power of the photons and what is the maximum kinetic energy of the ejected electrons?A light source is emitting radiation at 7.63•1014 Hz is incapable of ejecting photoelectrons from a certain metal. However, if the source is given a velocity of 0.28 c towards the metal, photoelectrons just begin to be ejected. A) What is the work function of the metal ? B) Determine the stopping voltage if the source is instead moved at 0.57 c towards the metal ?
- The work function for titanium is 4.33 eV. (a) Convert the value of the work function from electron volts to joules. J(b) Find the cutoff frequency for titanium. Hz(c) What maximum wavelength of light incident on titanium releases photoelectrons from the titanium's surface? nm(d) If light of energy 8.32 eV is incident on titanium, what is the maximum kinetic energy of the ejected photoelectrons? Give the answer in electron volts. eV(e) For photons of energy 8.32 eV, what stopping potential would be required to arrest the current of photoelectrons? VConsidering the photoelectric effect, if a liberated photoelectron has a maximum kinetic energy of 0.236 eV when light with a wavelength of 439 nm is being used, what is the work function of the material measured in eV?