A light source emitting radiation at 7.00 x 10¹4 Hz is incapable of ejecting photoelectrons from a certain metal. In an attempt to use this source to eject photoelectrons from the metal, the source is given a velocity toward the metal. (a) Explain how this procedure can produce photoelectrons.
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- The mathematical equation for studying the photoelectric effect is hν = W + 1/2 meu2 where ν is the frequency of light shining on the metal; W is the energy needed to remove an electron from the metal; and me and u are the mass and speed of the ejected electron, respectively. In an experiment, a student found that a maximum wavelength of 351 nm is needed to just dislodge electrons from a metal surface. Calculate the velocity (in m/s) of an ejected electron when the student employed light with a wavelength of 283 nm.Lithium has a work function of 2.51 eV. What is the maximum kinetic energy of the photoelectrons if 9.7 x 10¹4 Hz radiation is incident upon it?When monochromatic light of an unknown wavelength falls on a sample of silver, a minimum potential of 2.69 V is required to stop all of the ejected photoelectrons. (The work function for silver is 4.73 eV.) HINT (a) Determine the maximum kinetic energy (in eV) of the ejected photoelectrons. eV (b) Determine the maximum speed (in m/s) of the ejected photoelectrons. m/s (c) Determine the wavelength in nm of the incident light. nm
- Considering the photoelectric effect, if a liberated photoelectron has a maximum kinetic energy of 0.211 eV when light with a wavelength of 450 nm is being used, what is the work function of the material measured in eV? 1 eV = 1.602 x 10-19 JA light source emitting radiation at 7.00 x 10¹4 Hz is incapable of ejecting photoelectrons from a certain metal. In an attempt to use this source to eject photoelectrons from the metal, the source is given a velocity toward the metal. b) When the speed of the light source is equal to 0.280c, photoelectrons just begin to be ejected from the metal. What is the work function of the metal?Light with a frequency of (1.99x10^15) Hz hits a metal with a work function of (4.200x10^0) eV. Determine the maximum velocity of photoelectrons generated by this setup.
- Photons of wavelength 248.6 nm strike a metal whose work function is 3.5 eV. What is the KE of the most energetic photoelectron? a) 1.5 eV b) 2.5 eV c) 3.5 eV d) none of these.A light source is emitting radiation at 7.63•1014 Hz is incapable of ejecting photoelectrons from a certain metal. However, if the source is given a velocity of 0.28 c towards the metal, photoelectrons just begin to be ejected. A) What is the work function of the metal ? B) Determine the stopping voltage if the source is instead moved at 0.57 c towards the metal ?Considering the photoelectric effect, if a liberated photoelectron has a maximum kinetic energy of 0.236 eV when light with a wavelength of 439 nm is being used, what is the work function of the material measured in eV?