What is the kinetic energy of an electron that passes undeviated through perpendicular electric and magnetic fields if E = 4.0 kV/m and B = 8.0 mT?
What is the kinetic energy of an electron that passes undeviated through perpendicular electric and magnetic fields if E = 4.0 kV/m and B = 8.0 mT?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
What is the kinetic energy of an electron that passes undeviated through perpendicular electric and magnetic fields if \(E = 4.0 \, \text{kV/m}\) and \(B = 8.0 \, \text{mT}\)?
**Options:**
- \(0.84 \, \text{eV}\)
- \(0.65 \, \text{eV}\)
- \(0.54 \, \text{eV}\)
- \(1.4 \, \text{eV}\)
- \(0.71 \, \text{eV}\)
**Explanation:**
To find the kinetic energy of the electron, it needs to be in a balanced state where the electric force and magnetic force cancel each other. The electron's velocity \(v\) can be determined using the equation:
\[ v = \frac{E}{B} \]
Where:
- \( E = 4.0 \, \text{kV/m} = 4000 \, \text{V/m} \)
- \( B = 8.0 \, \text{mT} = 0.008 \, \text{T} \)
After calculating the velocity, you can find the kinetic energy \( KE \) using the equation:
\[ KE = \frac{1}{2} m v^2 \]
Where \( m \) is the mass of the electron (\( m \approx 9.11 \times 10^{-31} \, \text{kg} \)).
Convert \( KE \) from joules to electronvolts (1 eV \( = 1.6 \times 10^{-19} \, \text{J}\)) to match the options given.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75efe16f-f4aa-4987-9727-1ee0c2946a7c%2F1b0f977a-4d08-4d92-8add-2d6ab417c687%2Fthf4fg_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What is the kinetic energy of an electron that passes undeviated through perpendicular electric and magnetic fields if \(E = 4.0 \, \text{kV/m}\) and \(B = 8.0 \, \text{mT}\)?
**Options:**
- \(0.84 \, \text{eV}\)
- \(0.65 \, \text{eV}\)
- \(0.54 \, \text{eV}\)
- \(1.4 \, \text{eV}\)
- \(0.71 \, \text{eV}\)
**Explanation:**
To find the kinetic energy of the electron, it needs to be in a balanced state where the electric force and magnetic force cancel each other. The electron's velocity \(v\) can be determined using the equation:
\[ v = \frac{E}{B} \]
Where:
- \( E = 4.0 \, \text{kV/m} = 4000 \, \text{V/m} \)
- \( B = 8.0 \, \text{mT} = 0.008 \, \text{T} \)
After calculating the velocity, you can find the kinetic energy \( KE \) using the equation:
\[ KE = \frac{1}{2} m v^2 \]
Where \( m \) is the mass of the electron (\( m \approx 9.11 \times 10^{-31} \, \text{kg} \)).
Convert \( KE \) from joules to electronvolts (1 eV \( = 1.6 \times 10^{-19} \, \text{J}\)) to match the options given.
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