For the electron with a de broglie wavelength of 3.5 nm, what is the kinetic energy (in eV)?
For the electron with a de broglie wavelength of 3.5 nm, what is the kinetic energy (in eV)?
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Transcribed Image Text:Suppose you need to image the structure of a virus
with a diameter of 50 nm. For a sharp image, the
wavelength of the probing wave must be 5.0 nm or
less. We have seen that, for imaging such small
objects, this short wavelength is obtained by using
an electron beam in an electron microscope. Why
don't we simply use short-wavelength
electromagnetic waves? There's a problem with
this approach: As the wavelength gets shorter, the
energy of a photon of light gets greater and could
damage or destroy the object being studied. Let's
compare the energy of a photon and an electron
that can provide the same resolution.
For the electron with a de broglie wavelength of 3.5
nm, what is the kinetic energy (in eV)?
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