If you run an experiment where a = 0.05 and 3 = 0.18, a) What is the probability that you would reject the null and be correct to do so? b) What is the probability that you will not detect an effect even though it does exist?
Q: In a recent Super Bowl, a TV network predicted that 36 % of the audience would express an interest…
A: State the hypotheses. That is, the proportion of the audience would express an interest in seeing…
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A: 1. Given p = 16 n = 12 x = 3 P(X=x) = Cxn px (1-p)n-x ; x=0,1,2....n…
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A: From the provided information, Sample size (n) = 5 Chances that test comes back negative (p) = 0.998…
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A: Given that Test claim : A study to see if the average female life expectancy is significantly more…
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A: event A : gene mutationevent B : develop colon cancerP(A) = 1700P(B|A) = 0.55P(A∩B) = ?
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A: Proportion is almost similar to the concept of probability. Proportion is a fraction of a population…
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A: The information provided in the question are as follows :-Probability that a randomly selected…
Q: In a recent Super Bowl, a TV network predicted that 29 % of the audience would express an interest…
A: We have to find out test statistics z value..
Q: In a recent Super Bowl, a TV network predicted that 36 % of the audience would express an interest…
A:
Q: The CEO of a large electric utility claims that at least 80 percent of his one million customers are…
A: Assume that p is the true proportion of satisfied customers.
Q: In a recent Super Bowl, a TV network predicted that 27 % of the audience would express an interest…
A: Givensample size(n)=122x=38The null and alternative hypothesis is H0:p=0.27Ha:p<0.27
Q: Suppose a group of 700 smokers (who all wanted to give up smoking) were randomly assigned to receive…
A: From the provided information,
Q: Q. 2 A car dealer notes the following probabilities about his customers: P(those who buy a new car)…
A:
Q: In a recent Super Bowl, a TV network predicted that 21 % of the audience would express an interest…
A:
Q: In a recent Super Bowl, a TV network predicted that 39 % of the audience would express an interest…
A:
Q: A researcher is conducting an experiment to evaluate a treatment that is expected to increase the…
A: μ=100,x¯=105
Q: In a recent Super Bowl, a TV network predicted that 35 % of the audience would express an interest…
A: Given: Hypothesis: H0:p=0.35H0:p=0.35Ha:p>0.35Ha:p>0.35 Population, n = 123 Sample size, x =…
Q: opose are running a study/poll about the probability of a true negative on a test for a certain…
A: We have given that Sample size n = 109 Favorable cases x =71 Sample proportion p^=x/n = 71/109 =…
Q: Calculate the test statistic,
A: here In a recent Super Bowl, a TV network predicted that 54 % of the audience would express an…
Q: In a recent Super Bowl, a TV network predicted that 43 % of the audience would express an interest…
A: Consider that p is the true proportion of audience, who would express an interest in seeing one of…
Q: A study showed that 69.7% of occupants involved in a fatal car crash wore seat belts. Of those in a…
A:
Q: Suppose are running a study/poll about the probability of a true negative on a test for a certain…
A:
Q: H0:p=0.41 Ha:p≠0.41 Calculate the test statistic, rounde
A: Let x be the random variable such that the number of people who said they would watch one of the…
Q: n educational psychologist studies the effect of frequent testing on retention of class material. In…
A: Given, Frequent Quizzersn1=15M1=72SS1=112Two Examsn2=15M2=68SS2=98 The standard deviation of the two…
Q: A new study to determine the effectiveness of winter flu vaccinations measures the benefits of a flu…
A: From the given information we find the solution.
Q: is a 1.5% chance that you made a Type I error. there is a 2.5% chance that you made a Type I…
A:
Q: In a recent Super Bowl, a TV network predicted that 17 % of the audience would express an interest…
A: Let x be the number of people would watch one of the television shows. Here, x=31 and n=141 people…
Q: test to determine whether a certain antibody is present is 99.8% effective. This means that the…
A: Given that test to determine whether a certain antibody is present is 99.8% effective
Q: The decision is to (p-value = 0.092). There is the with student loan debt is hypothesis evidence…
A: Let p be the true proportion of college graduates who have student loan debt. Sample size (n) = 200…
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A: In hypothesis testing, a null hypothesis can be defined as the hypothesis of no difference or…
Q: In 1995, it was determined that 78% of US citizens supported a ban on household aerosols. Thinking…
A: Given that p=78%=0.78
Q: In a recent Super Bowl, a TV network predicted that 53 % of the audience would express an interest…
A: The random variable who watch one of the television shows is normally distributed. The population…
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A: Let A and B are two events then the baye's theorem has the formula,
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A:
Q: 66% of kids are worried about going back to school. In a random sample of 75 kids, what is the…
A: Here we need to find the required probability using binomial distribution.
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Q: (d) Decide whether to reject or fail to reject the null hypothesis. Choose the correct answer below.…
A: Given that Sample sizes n1=200 , n2=250 Sample proportion p1^=0.37 , p2^=0.49
Q: n a recent Super Bowl, a TV network predicted that 36 % of the audience would express an interest in…
A: Given that, The sample proportion is, Null and alternative hypothesis:
Q: The Wall Street Journal reported that approximately 25% of the people who are told a product is…
A: a) Let r be the random variable with number of people the product is infact improved. There are only…
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A: A study showed that the sex ratio of children born to families . Given: A news paper report about…
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A: The random sampling method is one of the sampling method. In this method, the elements of sample are…
Q: Quarters are currently minted with weights normally distributed and having a standard deviation of…
A: n=27, s=0.042, σ=0.069, α=0.05
Q: disease occurs in 1% of the population. A diagnostic test gives a positive result in: 99% of people…
A: Find P(disease/ positive) = ?
Q: ppose you are have the following null and alternative hypotheses for a test you are running:…
A: Given that A TV network predicted that 54 % of the audience would express an interest in seeing one…
Q: Part 3 of 4 If P=0.01, the result is statistically significant at the a= 0.05 level. The statement…
A: Part 1:-Given p=0.01α=0.01
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- could you please help me solve for the chi squared statistic, corresponding p value, and the bottom two questions about the null hypothesis?If the probability is below 0.01, the data provide strong evidence that the null hypothesis is false. show how?In a recent survey, 70% of management executives thought that it should be mandatory for business students to take a course in Quantitative methods. Fora random sample of 5 human resource directors, what is the probability that at least two of them think that it should not be mandatory for business students to take a quantitative methods course?
- It has recently been claimed that 25% of adults consider spring to be their favorite season of the year. A researcher is skeptical of this claim and believes this percentage is too low. She surveys a random of 1,000 adults and finds that 390 of these adults consider spring to be their favorite season of the year. As she prepares to conduct a hypothesis test, the researcher writes out her alternative hypothesis as “p < 0.25.” What is wrong with this? The alternative hypothesis should be “p > 0.39.” The alternative hypothesis should be “p < 0.39.” The alternative hypothesis should be “p > 0.25.” The alternative hypothesis should be “p = 0.25.” Nothing is wrong with the given alternative hypothesis.If you play roulettes and bet on 'red' the probability that you win is 18/38 = .4737. People often repeat this between several times. We can consider each time we play a 'trial' and consider it a success when we win, so p = 18/38 or (.4737) and q = 20/38 or (.5263). Suppose that Caryl always places the same bet when she plays roulette, $5 on 'red'. Caryl might play just once, or might play several times. She has a profit (having won $5 more times than she lost $5) if she wins more than half of the games she plays. -when you play 401 times, p is the proportion of those 401 games that you win. You'll profit (winning more than you lose) if you win more than half of your bets p > .5000. c) what is the mean or expected value of p? d) what is the standard deviation of p? e) assume that the distribution of p is Normal and find the probability that Caryl will have a profit if she plays 401 times. show your work or calculator input and round your answer to four decimal placesA new medical test has been designed to detect the presence of a certain disease. Among those who have the disease, the probability that the disease will be detected by the new test is 0.74. However, the probability that the test will erroneously indicate the presence of the disease in those who do not actually have it is 0.04. It is estimated that 14 % of the population who take this test have the disease.If the test administered to an individual is positive, what is the probability that the person actually has the disease?
- An educational psychologist studies the effect of frequent testing on retention of class material. In one of the professor's sections, students are given quizzes each week. The second section receives only two tests during the semester. At the end of the semester, both sections receive the same final exam, and the scores are summarized below. Do the data indicate that testing frequency has a significant effect on performance? Use a two-tailed test with α = .01. Include the null hypothesis in symbols, critical region(s), and a conclusion about significance. Compute r2 and state the size of the effect (e.g. small, medium, large). Frequent Quizzes Two Exams n = 15 n = 15 M = 72 SS= 112 M = 68 SS= 98In a recent Super Bowl, a TV network predicted that 23 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 137 people who saw the commercials and found that 36 of them said they would watch one of the television shows.Suppose you are have the following null and alternative hypotheses for a test you are running:H0:p=0.23Ha:p<0.23Calculate the test statistic, rounded to 3 decimal places z=A researcher sets his decision criteria at p = .01. That is, she decides that she will reject the null hypothesis if the z – value she obtains has a probability of .01 or less. What is this researcher’s probability of making Type I error?
- I want the answerYou are hiking through the woods, and come across some tracks; based on your expe- rience, you estimate there is a 40% chance the tracks are from a dog, a 30% chance the tracks are from a wolf, a 20% chance the tracks are from a coyote, and a 10% chance the tracks are from some other animal. Your friend, also a nature lover, notices some white hairs in the tracks. They know that 20% of dogs have white hair, 50% of wolves have white hair, 10% of coyotes have white hair, and 30% of other animals in the area have white hair. What are the odds of these tracks coming from a dog, wolf, coyote, or other animal?QUESTION 2 You conduct a study to understand whether happy people are more likely to exercise than sad people. In your sample of happy people. 25 chose to exercise and 10 chose to take a nap. In your sample of sad people, 5 chose to exercise and 35 chose to take a nap. (1) What is the null hypothesis? a. There is a difference in rates of exercise among happy and sad people. b. There is an association in rates of exercise among happy and sad people. c. There is not a difference in rates of exercise among happy and sad people. d. There is not an association in rates of happiness among those who exercise and those who nap. (2) What is the expected frequency for happy people who exercise? (3) What is the expected frequency for sad people who exercise? (4) What is the expected frequency for happy people who nap? (5) What is the expected frequency for sad people who nap? (6) What is your chi-square value? (7) How many degrees of freedom are there? (8) Assuming alpha is equal to .05, what is…