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MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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could you please help me solve for the chi squared statistic, corresponding p value, and the bottom two questions about the null hypothesis?

Two pea plants are crossed. One plant is homozygous for white blossoms and homozygous for being short, while the other plant is heterozygous for both blossom color and height. In pea plants, tall is dominant to short, and purple flowers are dominant to white. Fill out the table below for the probability of each possible phenotype. Report probability as a decimal rounded to four places (e.g. 0.1250, not 1/8 or 12.5%). Phenotype Probability tall purple • When performing a contingency table, do not round your expected values!! • Report your calculated x² rounded to four decimal places What is the corresponding P value? short purple • Use the formula =1-(CHISQ.DIST(X.df, TRUE)) to convert calculated X² into a P value • Report your answer rounded to 4 decimal places Do you fail to reject or reject the null hypothesis? tall white In a population of 150 pea plants, there are 39 tall-purple plants, 37 short-purple plants, 38 tall-white plants, and 36 short-white plants. In order to test if the two traits are experiencing independent assortment researchers would perform a chi squared test. The (null/alternative) null hypothesis states that the two genes are independently assorted while the (null/alternative) alternative hypothesis states the two genes are dependent. What is your calculated Chi Squared statistic? short white As a result of this statistical analysis, it is possible to conclude that pea plant height and pea plant blossom color (are or are not) linked traits.
Transcribed Image Text:Two pea plants are crossed. One plant is homozygous for white blossoms and homozygous for being short, while the other plant is heterozygous for both blossom color and height. In pea plants, tall is dominant to short, and purple flowers are dominant to white. Fill out the table below for the probability of each possible phenotype. Report probability as a decimal rounded to four places (e.g. 0.1250, not 1/8 or 12.5%). Phenotype Probability tall purple • When performing a contingency table, do not round your expected values!! • Report your calculated x² rounded to four decimal places What is the corresponding P value? short purple • Use the formula =1-(CHISQ.DIST(X.df, TRUE)) to convert calculated X² into a P value • Report your answer rounded to 4 decimal places Do you fail to reject or reject the null hypothesis? tall white In a population of 150 pea plants, there are 39 tall-purple plants, 37 short-purple plants, 38 tall-white plants, and 36 short-white plants. In order to test if the two traits are experiencing independent assortment researchers would perform a chi squared test. The (null/alternative) null hypothesis states that the two genes are independently assorted while the (null/alternative) alternative hypothesis states the two genes are dependent. What is your calculated Chi Squared statistic? short white As a result of this statistical analysis, it is possible to conclude that pea plant height and pea plant blossom color (are or are not) linked traits.
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