Given the half-cells: 2+ Ni/Ni²+ and Feo /Fe²+ a) Chose the anode and cathode. b) Calculate Eº and AG and K for this reaction. c) Calculate what the new cell potential (E) would be if the concentrations were [Ni²+] =.60 M and and [Fe+2] = .025M. d) If you let this battery run for 2 hours at 1.3 amps, what will be the new E for this battery?
Given the half-cells: 2+ Ni/Ni²+ and Feo /Fe²+ a) Chose the anode and cathode. b) Calculate Eº and AG and K for this reaction. c) Calculate what the new cell potential (E) would be if the concentrations were [Ni²+] =.60 M and and [Fe+2] = .025M. d) If you let this battery run for 2 hours at 1.3 amps, what will be the new E for this battery?
Chapter18: Introduction To Electrochemistry
Section: Chapter Questions
Problem 18.18QAP
Related questions
Question
Given the half-cells:
Ni/Ni2+ and Fe0 /Fe2+
a) Chose the anode and cathode.
b) Calculate Eo and Delta G and K for this reaction.
c) Calculate what the new cell potential (E) would be if the concentrations were [Ni2+] =.60
M and and [Fe+2] = .025M. If you let this battery run for 2 hours at 1.3 amps, what will
be the new E for this battery?
![Given the half-cells:
2+
Ni/Ni²+ and Feo /Fe²+
a) Chose the anode and cathode.
b) Calculate Eº and AG and K for this reaction.
c) Calculate what the new cell potential (E) would be if the concentrations were [Ni²+]
=.60 M and and [Fe+2] = .025M.
d) If you let this battery run for 2 hours at 1.3 amps, what will be the new E for this
battery?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fafd89ebb-9606-4f6f-8077-6730855609c1%2Fd5d5e767-b8f4-4fe0-932e-1eccdcde94d3%2Fuxzl8it_processed.png&w=3840&q=75)
Transcribed Image Text:Given the half-cells:
2+
Ni/Ni²+ and Feo /Fe²+
a) Chose the anode and cathode.
b) Calculate Eº and AG and K for this reaction.
c) Calculate what the new cell potential (E) would be if the concentrations were [Ni²+]
=.60 M and and [Fe+2] = .025M.
d) If you let this battery run for 2 hours at 1.3 amps, what will be the new E for this
battery?
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