If find f'(x). 4x(x + 2 tan(x)) sec (x) Find f'(4). 0 f(x) = 4x² tan r sec x

Q: F(x)= tan^-1(7x) Find, F'(x)=

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Q: 2x2 tan z If f(x) = find sec z f (x) = Find f (5)=

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Q: 2. Find f'(x): A. f(x)= 3x²+4 2x²-5

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Q: If f(x) = f'(x) = f'(2) = tan x 2 sec x 1 + 2 tan(x) sec(x)

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Q: If f(x) = f'(x) = f'(4) = tan x - 5 sec x 3x² tan(x) sec(x) X

A: The Quotient Rule:Use the common derivatives:

Q: find f'(x). 5x(x+2 tan(x)) sec (x) Find f'(3). f(x)= 5x² tan z sec z

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Q: If f(x) = 5 sec (3x), find f'(x). 15 sec (3x) tan (3x) Find f'(3).

A: We are given that f(x)=5 sec(3x)From the first part, we get f'(x)= 15 sec(3x) tan(3x)Now, we need to…

Q: If f(x)= f'(x) = f'(4) = = 3 tan x X " then

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Q: If f(x) = cos x 5 tan x, then ƒ'(x) = ƒ'(1) =

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Q: If f(x) = - f'(x) = f'(5) = 2 sin r 3 + cos x 3 then

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Q: If f(x) = 6 + Find f'(3). X 3 x² " find ƒ'(x).

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Q: If f (x) = (-2x)tan- (x³), what is f' (x) ? o f'(x) = –2(3x³ + tan¬1 %3D t3 o f'(x) = 2 ( - tan-!x'…

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Q: If f(x) = 2 tan-'(8 sin(4x)), f'(x) =

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Q: If find f'(x) f(x) = = 5x² tan x sec x

A: Given :fx=5x2tanxsecx

Q: Find f' (x) for 7 sec(r) f(x) = 4(1 + 5 tan(æ)) f' (x) = ||

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Q: If f(x) = f'(x) = f'(1) = = tan a - sec x 4

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Q: If f(x) = tan ¹(72³), find f'(x). Use exact values. f'(x) =

A: If , then to find .

Q: Where does the original function f(x) increases and decreased

A: f'(x) = +ve→f(x) will be increasing in this range.f'(x) = -ve→f(x) will be decreasing in this…

Q: If f(x) = f'(x) = = f'(4) = 3 tan x, then -sin(x) - 3 sec²(x) COS X >

A: we need to find out the derivative for the given function

Q: If f(x) = 3 sec(6x), find ƒ'(x). 18 sec (6x) tan (6x) Find f'(5).

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Q: If f(x)= 5x sin x cos x, find f'(x) and f'(3)

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