If f(x) = f'(x) = f'(1) = = tan a - sec x 4

Q: Find_f'(x) 16. f(x) = sec² x - tan² x

A:

Q: 3x2 tan x If f(x) sec x

A:

Q: tan(x) - 3 sec(x) If f(x) = - f'(x) = f'(-2) = then:

A: The given function is: fx=tanx-3secx   As we know that; The Quotient rule: fg'=f'·g-g'·fg2 And Use…

Q: f(x) = sec(x) tan(x), then f'(3t) =

A: First derivate then put the value

Q: If f(x) = f'(x) = f'(4) = tan x - 5 sec x 3x² tan(x) sec(x) X

A: The Quotient Rule:Use the common derivatives:

Q: Determine f '(x) for function f(x)= x2 tan x

A: Firstly, we use product rule of differentiation, which is (uv)'=uv'+u'v as shown on board.

Q: If f(x)= f'(x) = f'(4) = = 3 tan x X " then

A:

Q: take the derivative. g(x) = sec' x-(x° +3)

A: Our Aim is to take the derivative of g(x)=(sec3 (x) (x5+3)) -(i)

Q: If f(x) = sin x, find ƒ'(x) 5 5 sin(x) cos(x) Find f'(2)

A:

Q: If find f'(x) f(x) = = 5x² tan x sec x

A: Given :fx=5x2tanxsecx

Q: If y=Incscx, then the value of first derivative (y) is

A: The given function is y=ln cscx.

Q: Find f'(a) f(x) = 4x^2 -5x + 3

A:

Q: x sin x f(x) = = -9e | f'(x) =

A: Use product and chain rule of derivative

Q: If f(x) = 3 sec(6x), find ƒ'(x). 18 sec (6x) tan (6x) Find f'(5).

A:

Q: Determine f '(x)

A: Given:The function is

Q: (cos(X^2))^2  Find f'(x)

A: