If f(x) = f'(x) = f'(4) = tan x - 5 sec x 3x² tan(x) sec(x) X

Q: If f(x) = 4x(sin x + cos a), find f'(x) = COS f'(2) =

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A: Given: The function fx=2x+cos2xtanx Find the derivative of the given function Formula used: The…

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Q: tan(x) - 3 sec(x) If f(x) = - f'(x) = f'(-2) = then:

A: The given function is: fx=tanx-3secx   As we know that; The Quotient rule: fg'=f'·g-g'·fg2 And Use…

Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

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A: First derivate then put the value

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Q: If f(x)= f'(x) = f'(4) = = 3 tan x X " then

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Q: Let f(x) = f'(x) = - - 9 cos x + 4 tan x ƒ'( - 7) = =

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Q: If f(x) ƒ'(x) = f'(1) = = cos x – 5 tan x, then

A: Given that, f(x)=cosx-5tanx

Q: If f(x) = cos x 5 tan x, then ƒ'(x) = ƒ'(1) =

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Q: Let h(x) = tan(3x + 4). Then h' (2) is and h'' (2) is

A: The function is given by hx = tan3x+4 To evaluate: The values of h'2 and h''(2)

Q: If f (x) = (-2x)tan- (x³), what is f' (x) ? o f'(x) = –2(3x³ + tan¬1 %3D t3 o f'(x) = 2 ( - tan-!x'…

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Q: If A and B are constants, find where f''(x) = 0 I= f(x) = 9 Ar² + 7. Bx³

A: Since you have posted multiple questions i can do first question as per our company guidelines…

Q: Let f(x) = x² tan-'(8x) f'(x) =

A: Given: Now,

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Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: If find f'(x) f(x) = = 5x² tan x sec x

A: Given :fx=5x2tanxsecx

Q: If f(x) = f'(x) = f'(1) = 5 sin x 3+ cos x then

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Q: = 5 sec x tanx %3D

A: Please refer to the image below

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Q: If f(x) = f'(x) = f'(1) = = tan a - sec x 4

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Q: If f(x) = f'(x) = = f'(4) = 3 tan x, then -sin(x) - 3 sec²(x) COS X >

A: we need to find out the derivative for the given function

Q: IF g(x) = sin(x), then g'(x) = cos (x) 9₁ (3) = IF F(X) = (sin x + 8 cos x, then F'(x) = 6 COS (X) -…

A: Since you have posted a question with multiple question, we will solve first two question for you…

Q: = If f(x) = f'(x) = ƒ'(5) = 4 tan x, then - sin(x)-4 sec² (x) Cos x

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