) If available address lines are 36, then the possible addressable memory =________in bytes. Alternatively, if given addressable Memory = 256MB, then possible address lin
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A) If available address lines are 36, then the possible addressable memory =________in bytes.
Alternatively, if given addressable Memory = 256MB, then possible address lines are =_____?
(Subject: Computer Archetecture)
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- Given the following memory maps, determine the size of available memory space (ie the unused or free memory space). Convert your result to Kilobytes a) Memory 1 $0000 DIRECT PAGE REGISTERS $005F $0060 RAM 512 BYTES $025F $1800 HIGH PAGE REGISTERS $184F SE000 FLASH 8192 BYTES $FFFF b) Memory 2 |FFFFFH EPROM (128K) Flash Memory (128K) E0000h C0000h Unused 72000h Zilog SCC 70000h Unused 20000h SRAM (128K) 00000hWhen address binding is done at run time, Physical address space is A. the set of all addresses generated by the CPU B. the set of all addresses seen by the memory unitC. all of the above D. none of the above6. Assume a computer has 32-bit integers. Show how the value 0x0001122 would be stored sequentially in memory, starting at address 0x000, on both a big endian machine and a little endian machine, assuming that each address holds one byte. Address Big Endian Little Endian0x000 0x001 0x002 0x003
- Computer Science This question is about paging-based virtual memory A computer has a virtual-momory space of 250MB (megabytes) The computer has 325) of primary memory. The pige som s-4000 by the address is 1011 0001 0101 1110 0010 1010 0010 a. How many frames can it have? b. Which of the bits in the virtual address correspond to the Page number? c. Which of the bits correspond to the page offset?Oeew s Sat DO D 4 Hene et e H P E Dei vi At D Metig eta O t TE Fie • REC In Net ASSIGNMENT 1. The table below presents a list of devices that are to be addressed in a certain memory space. They have been ordered in the manner in which S S they are to be addressed with the first component being placed on the upper end of memory, starting at address $000000. By considering the size each component, provide the start and end address using the appropriate hexadecimal value. l Device Description Device Name Amount of memory to address ROM Chip ROM 1 RAM 1 4KB RAM Chip 8KB ROM Chip ROM 2 4KB Peripheral PER 1 4 bytes Peripheral PER 2 2 bytes 2. Assume a very simple microprocessor with 12 address lines Let's assume we wish to implement all its memory space and we use 517x8 memory chigs. a. What is the size of the largest addressable memory? 1aa H Q O B CEOESuppose that DS=1000H, SS= 2000H, CS=3000H, ES=4000H, BP=FFH, BX=FFFFH and DI=5H.i. Which memory locations are addressed by: MOV DL, [BP]?ii. Which memory locations are addressed by: MOV EAX, [BX+DI]?
- Consider a program consists of five segments: S0 = 600, S1 = 14 KB, S2= 100 KB, S3 =580 KB and S4 = 96 KB. Assume at that time, the available free space partitions of memory are 1200–1805, 50 – 150, 220-234, and 2500-3180.Find the following:d. What are the addresses in physical memory for the following logical addresses: 0.580, (b) 1.17 (c) 2.66 (d) 3.82 (e) 4.20?Problem 6. Nowadays the virtual address is much larger (64 bits) than the physical address space (e.g., on my MacBook, 35 bits). However, in "the old days" (early 80's), it could be the other way around. For example, on a PDP11/70 minicomputer runing UNIX, each process had a 64 KB (16 bit) virtual address space, while the machine had a 2 Megabyte physical memory. The virtual address space was divided into 8 pages of 8 Kbytes each. Thus each process had a page table with 8 entries. a. How big (how many bits) were the physical addresses in this system? b. How many high-order bits of the virtual address made up the virtual page number? c. How many bits are the offset in the page, and the physical page slot number? d. In the table below, you are given virtual-to-physical address mappings. For each one, say what page table entry was used, and what it contained, i.e., what the corresponding virtual page number (VP#, i.e., index into the page table) and physical page number (PP#, i.e.,…Q12/Assume that the microprocessor can directly address 1M with a and 8 data pins, The maximum RAM system can design by using the following RAM chips is Size of RAM chip Number of chips | 2K x 4 4К x 4 1KX4 5 512 x8 10 24KX8 O 27K x8 None of them 26K x8 25K x8
- According to the memory view given below, if RO = 0x20008000, then LDRSB r1, r1 = ?(data overlay big endian)? Memory address Data Øx20008002 ØXA1 Øx20008001 ØXB2 Øx20008000 ØxC3 ØX20007FFE ØXD4 ØX20007FFE OXE5 (Ctrl) A-R1 = 0XC3 B-R1 = 0x000000C3 C-R1 = OXC3000000 D-R1 = 0xffffffC3 E-R1 = OxC3ffffffRead-only memory (usually known by its acronym, ROM) is a class of storage media used in computers and other electronic devices that is non-volatile (non-changeable). Because data stored in ROM cannot be modified (at least not very quickly or easily), it is mainly used to distribute firmware (software that is very closely tied to specific hardware, and unlikely to require frequent updates). Figure 3.1 depicts a ROM block diagram which have k-bit address and an n-bit data. The contents of a ROM chip are defined once. Hence, we can use a constant array to model a ROM in VHDL. Basically, to name the size of a ROM is by stating ROM k x n, which represents ROM with k-bit address andn-bit data size. For example, ROM 4x8 (16 address location with each location containing 8-bit data). Question. Develop a code to allow the ROM operation works in synchronous when a read enable is asserted.• Generate and simulate the VHDL codes in Altera Quartus II.• Demonstrate and obtain the instructor…Physical address is formed from segment address & offset address. Select one: O True O False