Identify the structures of isomers H and I (molecular formula C&HuN).a. Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm2H5 H2H2H0234567ppmb. Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm13 H5 H1 H2 H328547

(a)Analyzing the IR Spectrum:The absorption peak at 3365 cm-1 and 3284 cm-1 corresponds to N–H…

Answered: Identify the structures of isomers H…

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter21: Benzene And The Concept Of Aromaticity

Section: Chapter Questions

Problem 21.20P

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The 13C-NMR spectrum of 3-methyl-2-butanol shows signals at 17.88 (CH3), 18.16 (CH3), 20.01 (CH3), 35.04 (carbon-3), and 72.75 (carbon-2). Account for the fact that each methyl group in this molecule gives a different signal.
Identify the structures of isomers H and I (molecular formula C8H11N).a.Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm−1b.Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm−1
Identify the structures of isomers H and I (molecular formula C8H11N).a.) Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and1497 cm−1 b.) Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and1492 cm−1
Compound C has molecular formula C5H8O. The IR, mass, 1H-NMR, and 13C-NMR spectra are shown below. Suggest a structure for C and explain your reasoning.
The 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.
14. Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.
Propose possible structures consistent with each set of data. Assume each compound has an sp3 hybridized C – H absorption in its IR spectrum, and that other major IR absorptions above 1500 cm are listed. a. a compound having a molecular ion at 72 and an absorption in its IR spectrum at 1725 cm−1 b. a compound having a molecular ion at 55 and an absorption in its IR spectrum at ~2250 cm−1 c. a compound having a molecular ion of 74 and an absorption in its IR spectrum at 3600–3200 cm−1
Propose possible structures consistent with each set of data. Assume each compound has an sp3 hybridized C—H absorption in its IR spectrum, and that other major IR absorptions above 1500 cm−1 are listed. a.a compound having a molecular ion at 72 and an absorption in its IR spectrum at 1725 cm−1 b. a compound having a molecular ion at 55 and an absorption in its IR spectrum at −2250 cm−1 c.a compound having a molecular ion at 74 and an absorption in its IR spectrum at 3600−3200 cm−1
This is the 13C spectrum for an X compound with molecular formula C7H12O4. The substance is not soluble in NaHCO3 and has a stretch at 1740cm-1 on the IR spectrum. What is the structure of X?
Molecular Formula: C7H10O IR: Only notable main absorptions is at 1710, 2945, and 3100 cm-¹ ¹H spectrum 1H, s 13C spectrum 200 180 160 140 3H, s 2H, t J = 7.1 Hz 2H, d J = 7.1 Hz dr 2H, t J = 7.1 Hz PPM 120 PPM 100 80 60 0 I T 40 20
Identify the structures of isomers E and F (molecular formula C4H8O2). Relative areas are given above each signal. a.Compound E: IR absorption at 1743 cm−1b.Compound F: IR absorption at 1730 cm−1
The 1H-NMR spectrum of ethanol shows a triplet at 1.23 ppm, a singlet at 2.61 pm, and a quartet at 3.69 ppm. Assign each signal to the protons it corresponds to in the molecule. Explain the splitting pattern observed for each signal.

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Identify the structures of isomers H and I (molecular formula C&HuN). a. Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm 2H 5 H 2H 2H 0 2 3 4 5 6 7 ppm b. Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm1 3 H 5 H 1 H 2 H 3 2 8 5 4 7