**Equilibrium Constant Expression for the Reaction****Reaction:**\[ \text{SO}_2(g) + \text{NO}_2(g) \rightleftharpoons \text{SO}_3(g) + \text{NO}(g) \]Given that the value of \( K_c \) for the reaction is 2.50, identify the equilibrium constant expression.**Options:****A.**\[ 2.50 = \frac{[\text{SO}_3][\text{NO}]}{[\text{SO}_2][\text{NO}_2]} \]**B.** *(Correct Answer)*\[ 2.50 = \frac{[\text{SO}_2][\text{NO}_2]}{[\text{SO}_3][\text{NO}]} \]**C.**\[ 2.50 = \frac{(P_{\text{SO}_3})^3(P_{\text{NO}})}{(P_{\text{SO}_2})^2(P_{\text{NO}_2})^2} \]**D.**\[ 2.50 = \frac{(P_{\text{SO}_3})(P_{\text{NO}})}{(P_{\text{SO}_2})(P_{\text{NO}_2})} \]**Explanation:** The equilibrium constant expression is a ratio of the concentrations (or pressures) of the products to the reactants, each raised to the power of their coefficients in the balanced equation. Here, option B correctly represents the inverse concentration expression expected for a \( K_c \) value of 2.50 given the directions in the problem statement.

Answered: Image /qna-images/answer/8bbbb345-0b58-4c2f-8614-3c06d6d10424.jpg

Identify the equilibrium constant expression for the reaction so,(3) + NO,(3) = so,(g) +NO(g) given that the value of Ke for the reaction is 2.50. Choose one: Ο Α. [so3][NO] 2.50 = [so,][NO,] В. 2.50 = [so.][NO,] [so,][NO] (Pso,) (Pxo) (Pso,(Fso, OC. 2.50 = (Pso,)(Pxo) (Pso,)(Pxo,) O D. 2.50 = NO

Identify the equilibrium constant expression for the reaction so,(3) + NO,(3) = so,(g) +NO(g) given that the value of Ke for the reaction is 2.50. Choose one: Ο Α. [so3][NO] 2.50 = [so,][NO,] В. 2.50 = [so.][NO,] [so,][NO] (Pso,) (Pxo) (Pso,(Fso, OC. 2.50 = (Pso,)(Pxo) (Pso,)(Pxo,) O D. 2.50 = NO

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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