Knowing that [reactant]Ó = [reactant]initial - [reactant]onsumedAnd thatFe"(aq) + SCN'(aq) Ó Fe(SCN)+*(aq)Complete the table below and determine an average value for the equilibriumconstant K.Exp#1exp#2exp#3[Fe*1° (M)1.65 x 101.65 x 1031.65 x 103[SCN]° (M)3.30 x 106.60 x 109.90 x 104[Fe(SCN)*jÓ (M)9.00 x 1051.78 x 102.67 x 10[Fe*jóISCNJÓKAverage K =Fe"(aq) +SCN (aq) ó Fe(SCN)**(aq)I1.65 x 10-9.00 x 10°3.30 x 10-9.00 x 105C0.00+9.00 x 109.00 x 10$

Answered: Image /qna-images/answer/95e1afc2-440d-49f2-bc48-36b77e6cce22.jpg

consumed Knowing that [reactant]Ó = [reactant]nitial- [reactant] And that Fe"(aq) + SCN(aq) Ó Fe(SCN)"(aq) Complete the table below and determine an average value for the equilibrium constant K. Еxp#1 exp#2 exp#3 [Fe*1° (M) 1.65 x 103 1.65 x 10 1.65 x 10 [SCN] (M) 3.30 x 104 6.60 х 104 9.90 x 104 [Fe(SCN)*JÓ (M) 9.00 x 105 1.78 x 10 2.67 x 104 [Fe"jÓ ISCNJÓ ........ ..... Average K = ...... Fe" (aq) + SCN (aq) ó Fe(SCN)**(aq) I 1.65 x 10 -9.00 x 10 3.30 x 104 C 0.00 -9.00 x 10 +9.00 x 10 9.00 x 10

consumed Knowing that [reactant]Ó = [reactant]nitial- [reactant] And that Fe"(aq) + SCN(aq) Ó Fe(SCN)"(aq) Complete the table below and determine an average value for the equilibrium constant K. Еxp#1 exp#2 exp#3 [Fe1° (M) 1.65 x 103 1.65 x 10 1.65 x 10 [SCN] (M) 3.30 x 104 6.60 х 104 9.90 x 104 [Fe(SCN)JÓ (M) 9.00 x 105 1.78 x 10 2.67 x 104 [Fe"jÓ ISCNJÓ ........ ..... Average K = ...... Fe" (aq) + SCN (aq) ó Fe(SCN)**(aq) I 1.65 x 10 -9.00 x 10 3.30 x 104 C 0.00 -9.00 x 10 +9.00 x 10 9.00 x 10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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