70. This reaction is exothermic. C,H12O6(s) + 6 O2(g) =6 CO2(g) + 6 H2O(g) Predict the effect (shift right, shift left, or no effect) of increas- ing and decreasing the reaction temperature. How does the value of the equilibrium constant depend on temperature?
70. This reaction is exothermic. C,H12O6(s) + 6 O2(g) =6 CO2(g) + 6 H2O(g) Predict the effect (shift right, shift left, or no effect) of increas- ing and decreasing the reaction temperature. How does the value of the equilibrium constant depend on temperature?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![### Exothermic Reaction Analysis
**Reaction:**
\[ C_6H_{12}O_6(s) + 6 O_2(g) \rightleftharpoons 6 CO_2(g) + 6 H_2O(g) \]
**Question:**
Predict the effect (shift right, shift left, or no effect) of increasing and decreasing the reaction temperature. How does the value of the equilibrium constant depend on temperature?
**Explanation:**
In an exothermic reaction, heat is released. According to Le Chatelier's principle, if the temperature is increased, the system will adjust to counteract this change. Therefore:
- **Increasing Temperature:** The equilibrium will shift to the left to absorb the excess heat.
- **Decreasing Temperature:** The equilibrium will shift to the right to produce more heat.
**Equilibrium Constant Dependence:**
For exothermic reactions, the equilibrium constant decreases with an increase in temperature because the reaction shifts towards reactants. Conversely, the equilibrium constant increases when the temperature decreases, as the reaction favors the formation of products.
This analysis is crucial for understanding how temperature variations impact reaction dynamics and equilibrium positions in chemical processes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a4554f8-c4a9-4782-b993-e17cc0d7a5f8%2F469873cf-63db-490b-8b7b-bf0e343e5ed0%2Fnftfio_processed.png&w=3840&q=75)
Transcribed Image Text:### Exothermic Reaction Analysis
**Reaction:**
\[ C_6H_{12}O_6(s) + 6 O_2(g) \rightleftharpoons 6 CO_2(g) + 6 H_2O(g) \]
**Question:**
Predict the effect (shift right, shift left, or no effect) of increasing and decreasing the reaction temperature. How does the value of the equilibrium constant depend on temperature?
**Explanation:**
In an exothermic reaction, heat is released. According to Le Chatelier's principle, if the temperature is increased, the system will adjust to counteract this change. Therefore:
- **Increasing Temperature:** The equilibrium will shift to the left to absorb the excess heat.
- **Decreasing Temperature:** The equilibrium will shift to the right to produce more heat.
**Equilibrium Constant Dependence:**
For exothermic reactions, the equilibrium constant decreases with an increase in temperature because the reaction shifts towards reactants. Conversely, the equilibrium constant increases when the temperature decreases, as the reaction favors the formation of products.
This analysis is crucial for understanding how temperature variations impact reaction dynamics and equilibrium positions in chemical processes.
Expert Solution

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The given reaction is :
The above reaction is exothermic.
We have to predict the effect of changing the temperature of the reaction.
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