At -6.59 °C the pressure equilibrium constant K, =9.4 × 10° for a certain reaction. Here are some facts about the reaction: • The initial rate of the reaction is 14. mol·L¯'s. • If the reaction is run at constant pressure, the volume increases by 11.%. • The net change in moles of gases is -2. O Yes. Using these facts, can you calculate K, at – 12. °C? O No. If you said yes, then enter your answer at right. Round it to 2 significant digits. Yes, and K, will be bigger. If you said no, can you at least decide whether K, at Yes, and K, will be -12. °C will be bigger or smaller than K, at -6.59 °C? smaller. O
At -6.59 °C the pressure equilibrium constant K, =9.4 × 10° for a certain reaction. Here are some facts about the reaction: • The initial rate of the reaction is 14. mol·L¯'s. • If the reaction is run at constant pressure, the volume increases by 11.%. • The net change in moles of gases is -2. O Yes. Using these facts, can you calculate K, at – 12. °C? O No. If you said yes, then enter your answer at right. Round it to 2 significant digits. Yes, and K, will be bigger. If you said no, can you at least decide whether K, at Yes, and K, will be -12. °C will be bigger or smaller than K, at -6.59 °C? smaller. O
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter13: Chemical Equilibrium
Section: Chapter Questions
Problem 129MP: A gaseous material XY(g) dissociates to some extent to produce X(g) and Y(g): XY(g)X(g)+Y(g) A...
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