Identify the electrophile and the nucleophile in each of the following reaction steps. Then draw curved arrows to illustrate the bond-making and bond-breaking processes.

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Identify the electrophile and the nucleophile in each of the following reaction steps. Then draw curved arrows to illustrate the bond-making and bond-breaking processes.

 

### Chemical Reactions Involving Organic Compounds

**Equation 1: Bromine Addition to a Cyclopropane Compound**

The first reaction shows the addition of bromine to a cyclopropane compound.

Reactants:
- Cyclopropane derivative with a bromine atom attached: \( \text{CH}_3\text{CH}_2\text{C}(\text{Br})\text{CH} \)
- Bromine molecule: \( \cdot \text{Br}_2 \)

Reaction:
\[ \text{CH}_3\text{CH}_2\text{CBr-CH} + \cdot \text{Br}_2 \rightarrow \text{CH}_3\text{CH}_2\text{CBr}_2\text{CH} \]

Explanation:
- A cyclopropane derivative with a single bromine (attached to the middle carbon) reacts with a diatomic bromine molecule.
- The product is a compound where the double-bonded carbon now has two bromine atoms attached.

**Equation 2: Deprotonation of Alkyne by Ammonia**

The second reaction shows the deprotonation of an alkyne by ammonia.

Reactants:
- Ethyne derivative: \( \text{CH}_3\text{C} \equiv \text{C-H} \)
- Ammonia with its lone pair: \( \cdot \text{NH}_2 \)

Reaction:
\[ \text{CH}_3\text{C} \equiv \text{C-H} + \cdot \text{NH}_2 \rightarrow \text{CH}_3\text{C} \equiv \text{C}- \text{NH}_3 \]

Explanation:
- An ethyne derivative reacts with an ammonia molecule.
- The alkyne undergoes deprotonation by the ammonia, resulting in a nitrile and a protonated ammonia molecule.

These reactions are fundamental examples demonstrating mechanisms such as bromine addition and deprotonation in organic chemistry.
Transcribed Image Text:### Chemical Reactions Involving Organic Compounds **Equation 1: Bromine Addition to a Cyclopropane Compound** The first reaction shows the addition of bromine to a cyclopropane compound. Reactants: - Cyclopropane derivative with a bromine atom attached: \( \text{CH}_3\text{CH}_2\text{C}(\text{Br})\text{CH} \) - Bromine molecule: \( \cdot \text{Br}_2 \) Reaction: \[ \text{CH}_3\text{CH}_2\text{CBr-CH} + \cdot \text{Br}_2 \rightarrow \text{CH}_3\text{CH}_2\text{CBr}_2\text{CH} \] Explanation: - A cyclopropane derivative with a single bromine (attached to the middle carbon) reacts with a diatomic bromine molecule. - The product is a compound where the double-bonded carbon now has two bromine atoms attached. **Equation 2: Deprotonation of Alkyne by Ammonia** The second reaction shows the deprotonation of an alkyne by ammonia. Reactants: - Ethyne derivative: \( \text{CH}_3\text{C} \equiv \text{C-H} \) - Ammonia with its lone pair: \( \cdot \text{NH}_2 \) Reaction: \[ \text{CH}_3\text{C} \equiv \text{C-H} + \cdot \text{NH}_2 \rightarrow \text{CH}_3\text{C} \equiv \text{C}- \text{NH}_3 \] Explanation: - An ethyne derivative reacts with an ammonia molecule. - The alkyne undergoes deprotonation by the ammonia, resulting in a nitrile and a protonated ammonia molecule. These reactions are fundamental examples demonstrating mechanisms such as bromine addition and deprotonation in organic chemistry.
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