Idealize the Earth as a perfect sphere of radius R = 6371 km. If you could measure distances with an error of ±1 meter, how large a circle would you have to draw on the Earth’s surface to convince yourself that the Earth is spherical rather than flat? Note that (or prove yourself) on the surface of a sphere, a circle of radius r will have a circumference of C = 2πR sin(r/R). Round your answer to the nearest whole number. Hint: recall that you can approximate sin(x) with a Taylor series expansion: sin(x) \approx≈ x - x3/3! Answer value
Idealize the Earth as a perfect sphere of radius R = 6371 km. If you could measure distances with an error of ±1 meter, how large a circle would you have to draw on the Earth’s surface to convince yourself that the Earth is spherical rather than flat? Note that (or prove yourself) on the surface of a sphere, a circle of radius r will have a circumference of C = 2πR sin(r/R). Round your answer to the nearest whole number. Hint: recall that you can approximate sin(x) with a Taylor series expansion: sin(x) \approx≈ x - x3/3! Answer value
Related questions
Question
Idealize the Earth as a perfect sphere of radius R = 6371 km. If you could measure distances with an error of ±1 meter, how large a circle would you have to draw on the Earth’s surface to convince yourself that the Earth is spherical rather than flat? Note that (or prove yourself) on the surface of a sphere, a circle of radius r will have a circumference of C = 2πR sin(r/R).
Round your answer to the nearest whole number.
Hint: recall that you can approximate sin(x) with a Taylor series expansion: sin(x) \approx≈ x - x3/3!
Answer value
Expert Solution
Step 1
Given Data :
R = 6731 km
C = 2πR sin (r/R)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
