College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
How do I find the slope or if my graph is correct

Transcribed Image Text:Figure 4. How to correctly measure the position of the bottom of the spring when the
weight hanger carries the required added masses.
M₁ (g) =
MSW
(8)
50
100
150
200
250
Table # 1: Determination of the spring constant K
X₁ (cm) = _, 2
MT= Mh+Msw
MT
(8)
MT
(kg)
8 = 9.80 m/s²
F=W=MT g
FK
(N)
0
6.6.5. 0.066.5
0.6517
1/6:52 0.116.5 1.1417
xf
(cm)
13.3
166.5 0.166.5 1.63/7 4.9
44
216.2 0.2165 212/7
266.55 02. 266.5
6.9
x = xf- Xo
10.2
2.6/17 8
X
(cm)
x
(m)
0
Average force constant Kavg
Force constant Ktren from the slope of the trendline in the graph
% relative difference between Kavg and Ktren
Mh: Mass of the weight hanger
Msw: Mass of added slotted weights
Mr: Total Mass
W: Weight of hanger plus slotted weights
aq
K =
F(N)
x(m)
0.2 0.1
6517
2.5ch 0.025 45.068
You 0.09 40,7925
0:055 38.576 3 6 3 6 4
36.9736 LLL
35.7829 n/m
55
7.2 0.072
K
(N/m)
xo: Position of the spring's bottom (unstretched)
xf: Position of the spring's bottom (stretched)
x: Elongation of the spring
K: Force constant of the spring

Transcribed Image Text:g when the
F(N)
x(m)
(7)
A
7
8
25
H
I'm
G
2.607
2.1217
116317
1,1417
0.65/7
Figure.
Please show here the calculation of the slope.
Slope =
0.025 004 0055 0.072 00
x
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