We are going to make a simple approximation of the number of atoms in the universe.Assume all the atoms in the universe are hydrogen. (In actual practice, over 75% of the atoms in the universe are hydrogen.)Assume the sun is a typical star (made of pure hydrogen) has a density of 1.4 g/cm3 and is a sphere with a radius of 7.0*108mAssume that there are 100 billion stars in our Milky Way galaxy that are identical to our sun.Assume that there are 10 billion galaxies in the universe identical to our Milky Way galaxy. How many atoms are there in the universe?

Given that, Density of sun = 1.4 g/cm3 Radius of sun = 7.0×108 m =7.0×1010 cm Mass of the sun =…

Answered: We are going to make a simple…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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We are going to make a simple approximation of the number of atoms in the universe.

1. 1. Assume all the atoms in the universe are hydrogen. (In actual practice, over 75% of the atoms in the universe are hydrogen.)
  2. Assume the sun is a typical star (made of pure hydrogen) has a density of 1.4 g/cm³ and is a sphere with a radius of 7.0*10⁸m
  3. Assume that there are 100 billion stars in our Milky Way galaxy that are identical to our sun.
  4. Assume that there are 10 billion galaxies in the universe identical to our Milky Way galaxy.
    
    How many atoms are there in the universe?

Expert Solution

Step 1

Given that,

Density of sun = 1.4 g/cm³

Radius of sun = $7.0 \times 10^{8} m$ = $7.0 \times 10^{10} c m$

Mass of the sun = Density $\times$ Volume

putting the values

Mass of the sun = $1.4 \times \frac{4}{3} π {(7 \times 10^{10})}^{3} = 2.011 \times 10^{33} g$

Average atomic mass of hydrogen atom =1.008 amu

Avogadro's number = $6.02 \times 10^{23}$ of atoms in 1 mole of hydrogen

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