An object is placed 11 cm in front of a concave mirror whose focal length is 17 cm. The object is 3.8 cm tall. Determine (a) the location of the image, taking a real image as a positive value and a virtual image as a negative value. (b) Determine the height of the image, where an upright image will have a positive height and an inverted image will have a negative height. (a) Number i Units (b) Number i Units C F Object
An object is placed 11 cm in front of a concave mirror whose focal length is 17 cm. The object is 3.8 cm tall. Determine (a) the location of the image, taking a real image as a positive value and a virtual image as a negative value. (b) Determine the height of the image, where an upright image will have a positive height and an inverted image will have a negative height. (a) Number i Units (b) Number i Units C F Object
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I'm not understanding how you are getting the v in this problem. I understand you multiply the inverse of 1/v, but can't understand what v is and how you determine that number?

Transcribed Image Text:An object is placed 11 cm in front of a concave mirror whose focal length is 17 cm. The object is 3.8 cm tall. Determine (a) the location
of the image, taking a real image as a positive value and a virtual image as a negative value. (b) Determine the height of the image,
where an upright image will have a positive height and an inverted image will have a negative height.
(a) Number i
Units
(b) Number i
Units
C
F
Object
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