The figure gives the acceleration a versus time t for a particle moving along an x axis. The a-axis scale is set by as = 16.0 m/s². At t = -2.0 s, the particle's velocity is 7.00 m/s. What is its velocity at t = 6.0 s? Number i -25 Units -2 a (m/s²) Ag 0 m/s t(s)
The figure gives the acceleration a versus time t for a particle moving along an x axis. The a-axis scale is set by as = 16.0 m/s². At t = -2.0 s, the particle's velocity is 7.00 m/s. What is its velocity at t = 6.0 s? Number i -25 Units -2 a (m/s²) Ag 0 m/s t(s)
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I thought I was doing this correctly, but I guess not. I took the scale of 16/ms^2 and mutilied it by 4 to get the inital point Y value. Then subtracted the 2nd y value of zero and divided all of that by x2-x1 (0-4) to get the slope of -16. I then put that in the point slope formula to get a(t)=-16t+ 56. I then integrated to get v(t)=-8t^2+56t+C I solved for C to get -73. Then I plugged in the given time of 6 seconds to get -25.
Transcribed Image Text:Your answer is partially correct.
The figure gives the acceleration a versus time t for a particle moving along an x axis. The a-axis scale is set by as = 16.0 m/s². At t = -2.0
s, the particle's velocity is 7.00 m/s. What is its velocity at t = 6.0 s?
Number i -25
Units
a (m/s²)
Ag
-2 0
m/s
2
t(s)
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